Pure iodine (102 g) is dissolved in 325 g of CCl4 at 65 °C. Given that the vapor pressure of CCl4 at this temperature is 531 mm Hg, what is the vapor pressure of the CC14-12 solution at 65 °C? (Assume that I2 does not contribute to the vapor pressure.) Vapor pressure = mm Hg
Pure iodine (102 g) is dissolved in 325 g of CCl4 at 65 °C. Given that the vapor pressure of CCl4 at this temperature is 531 mm Hg, what is the vapor pressure of the CC14-12 solution at 65 °C? (Assume that I2 does not contribute to the vapor pressure.) Vapor pressure = mm Hg
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![Pure iodine (102 g) is dissolved in 325 g of CCl4 at 65 °C. Given that the vapor pressure of CC14 at this temperature is 531 mm Hg, what is the vapor pressure of
the CC14-12 solution at 65 °C? (Assume that I2 does not contribute to the vapor pressure.)
Vapor pressure =
mm Hg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e64e050-9cb6-467e-8132-ec94d7497579%2Fff26d328-0546-4f52-b0df-97ce85982e44%2Fihredee_processed.png&w=3840&q=75)
Transcribed Image Text:Pure iodine (102 g) is dissolved in 325 g of CCl4 at 65 °C. Given that the vapor pressure of CC14 at this temperature is 531 mm Hg, what is the vapor pressure of
the CC14-12 solution at 65 °C? (Assume that I2 does not contribute to the vapor pressure.)
Vapor pressure =
mm Hg
Expert Solution
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Step 1
Molecular weight of I2 = 253.81 g/mol
Number of moles of non-volatile solute (I2) = mass/mol.wt. = 102 g/(253.81 g/mol)= 0.40188 mol
Mass of CCl4 = 325 g
Molecular weight of CCl4 = 153.82 g/mol
Number of moles of solvent water = 325 g/(153.82 g/mol) = 2.11286 mol
Total number of moles = 0.40188 + 2.11286 = 2.51473 mol
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