Pulse rates A medical researcher measured the pulserates (beats per minute) of a sample of randomly selected adults and found the following Student’s t-based confi-dence interval: With 95.00% Confidence,70.887604 6 m1Pulse2 6 74.497011a) Explain carefully what the software output means.b) What’s the margin of error for this interval?c) If the researcher had calculated a 99% confidenceinterval, would the margin of error be larger orsmaller? Explain.

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A: Given: Sample Size (n)=226 Sample Mean (X)=37.3 Standard deviation (s)=7.2

Q: To find out how much fat is in a common hot dog, a nutritionist recorded the amount of fat in 100…

A: Given data is4,5,5.5,6,6.25,6.75,7,7.758,8sample size(n)=9

Q: You measure 28 randomly selected textbooks' weights, and find they have a mean weight of 68 ounces.…

A: Obtain the 99% confidence interval for the true population mean textbook weight.   The 99%…

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A: We have given that,  Sample mean (x̄) = 39.3, standard deviation (s)= 7.3 and sample size (n) = 68…

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A: Given,sample size(n)=36sample mean(x¯)=6240degrees of…

Q: For each question, find: Hypotheses   Type of test, level of significance  Test statistic  P-value…

A: Sample size, n=100 Sample mean, x¯=7.01 Sample sd, s=3.74

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A: given; n=10,   x¯=10 (sample mean),   σ=3 (population standard deviation)

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A:

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A: Given: A study was designed in which the relationship between smoking and work status was examined…

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A: Since the sample size is small and population standard deviation is unknown, t distribution can be…

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A: It is given that, the sample mean, x-bar = 6.87, n=1050 and the sample standard deviation, s =…

Q: Hny

A: To calculate the confidence interval for a population mean with a given confidence level, you can…

Q: A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 68…

A: Given, Sample size = 68 Sample mean = 41.3 Sample standard deviation = 6.7   Since the population…

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A: It is given that Population mean = 5.2 Sample mean = 4.25

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Q: None

A: We can solve for Confidence Interval of the difference in mean scores using this formula: a)CI =…

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A: Consider, Data 488 350 457 199 285 409 435 574 439 546 385 295 184…

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A: Given: Sample Mean \bar XXˉ = 20.320.3 Sample Standard Deviation (s)(s) = 18.218.2 Sample…

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A: xbar = 31 s = 8 n = 16

Q: What is the excel formula for this? A simple random sample of 60 items resulted in a sample average…

A: Given information- Sample size, n = 60 Sample mean, x-bar = 80 Sample standard deviation, σ = 15…

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A: Given,sample size(n)=132sample mean(x¯)=41.8standard deviation(s)=13.3degrees of…

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A: Given , n = 50  ∑x = 205 , ∑(x-x¯)2 = 56.43

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A:

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A: Sample mean = 65,900. Population standard deviation, σ is 16,973. The sample size, n is 43. Using…

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A: Sample  size(n)=90sample mean()=60Standard deviation()=15

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A: Followings are the Explanation of the question

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A:

Q: A 94 % confidence interval for the mean amount of coffee dispensed by vending machine is: (7.2, 7.6)…

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A: From the provided information, Sample size (n) = 9 Confidence level = 98%

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A: Let Y be the random variable representing the distances of certain raptor nests to the nearest…

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A:

Q: A manufacturer produces 1000 lightbulbs an hour from a given machine. An quality control engineer…

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A: Given : Sample Size, n = 234 Sample Mean, x̄ = 1.1 sample standard…

Q: Contstruct a 95% confidence interval for the population mean length of time that people have lived…

A: Here, mean is bit larger than the median, so we do not think that this variable has a normal…

Q: sample of eight math SAT scores is given below:   600530560700630640580680600530560700630640580680…

A: Eight scores given 600,530,560,700,630,640,580,680 First quartile (Q1) = (n+1)/4  th   term Third…

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.