Using a random sample of m&ms in a bag over the past five years, Jamie conducted a 95% confidence interval for the proportion of blue m&m's in the bags. The interval found is (0.7219, 0.8864). a) The interval above is a (choose one option): z-confidence or t-confidence interval  b) Calculate the sample proportion for this confidence interval. Use the correct notation c) Calculate the margin of error for this confidence interval . 3) If the level was changed to 99%, the width of the interval would be (choose one option): Larger or Smaller or No Change

Q: Use the given data to construct a 98%confidence interval for the population proportion p x = 52 , n…

A: We have given that,  Favorable cases (X) = 52 and sample size (n) = 69 Then,  We will find the 98%…

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A: From the provided information,Confidence level = 92.2%

Q: 1. Find the 98% confidence interval (CI) and margin of error (ME) for the mean heights of men when:…

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Q: If X = 114, α= 20, and n = 33, construct a 99% confidence interval estimate for the population mean,…

A: Given data:  Sample Mean = 114 Population standard deviation = 20 Sample size = 33 Confidence level…

Q: Construct the indicated confidence interval for the difference between population proportions p1 -…

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Q: If X=70​, σ=14​, and n=61​, construct a 99​% confidence interval estimate of the population​ mean,…

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Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

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Q: n your random sample of home prices. To insert a tion" or simply copy and edit the equation in the…

A: Formula : The confidence interval formula is CI =

Q: Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use…

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Q: A researcher is interested in a 95% confidence interval. It is found to have a point estimate of 2.5…

A: From the provided information, Confidence level = 95% Point estimate = 2.5 Margin of error (E) = 0.6

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Q: A poll of 2929 U.S. adults found that 85% regularly used Facebook as a news source. Find the…

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Q: A confidence interval for a population mean has a margin of error of 3.3. a) Determine the length…

A: Given data, Margin of Error(E)=3.3

Q: A​ 95% confidence interval for the proportion of U.S. adults who subscribe to some sort of streaming…

A: In the above question, we are given,  a confidence interval is

Q: A poll of 2657 U.S. adults found that 86% regularly used Facebook as a news source. Find the margin…

A: Given that, n = 2657 Point estimate = sample proportion =  = 0.86 1 -  = 1 - 0.86 = 0.14

Q: A poll of 2977 U.S. adults found that 28% regularly used Facebook as a news source. Find the margin…

A: Solution: Given information: n = 2977 Sample size  p^= 0.28  Sample proportion.

Q: A survey of folk music fans yield this 95% confidence interval estimate of the proportion of fans…

A: Introduction:The 95% confidence interval for the requires proportion is (0.74, 0.86). So, lower…

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Q: Use the given data to construct a confidence interval of the requested level. X = 178, N=531,…

A: Given : Sample Size, n = N = 531 Number of successes, x = 178

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

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Q: A software company is interested in improving customer satisfaction rate from the 55% currently…

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Q: Construct a 90​% confidence interval of the population proportion using the given information.…

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Q: In a survey of 2092 adults in a recent year, 748 made a New Year's resolution to eat healthier.…

A: Given data n=2092 x=748

Q: A poll of 1021 U.S. adults found that 46% regularly used Facebook as a news source. Find the…

A: Given, n = 1021 p^=0.46 q^ = 1 - p^ = 1 - 0.46 = 0.54 α=0.1

Q: Find a Confidence interval for the true Population Proportions if n = 30,        x = 75, and the…

A: From the given information, X=75 and n=30.

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A: The number of bean plants, n=136 The increased growth is 87%. i.e. p^=0.87 The confidence interval…

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A: From the given information, let X be the number of adults have made a New Year’s resolution. X =…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Given We have given that confidence interval (0.640 ,0.670) lower limit = 0.640  Upper limit = 0.670…

Q: A poll of 2368 U.S. adults found that 40% regularly used Facebook as a news source. Find the margin…

A: Solution: From the given information, n=2368, p-hat = 40%. The confidence level is 0.90.

Q: If X=68​, σ=14​, and n=66​, construct a 95​% confidence interval estimate of the population​ mean, μ

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