Modify the Contact class in Chapter 10 so that the sorting methods invoked in PhoneList.java keeps the Contact objects sorted by phone number. ```javapublic class PhoneList { public static void main (String[] args) { Contact[] friends = new Contact[8]; friends[0] = new Contact("John", "Smith", "610-555-7384"); friends[1] = new Contact("Sarah", "Barnes", "215-555-3827"); friends[2] = new Contact("Mark", "Riley", "733-555-2969"); friends[3] = new Contact("Laura", "Getz", "663-555-3984"); friends[4] = new Contact("Larry", "Smith", "464-555-3489"); friends[5] = new Contact("Frank", "Phelps", "322-555-2284"); friends[6] = new Contact("Mario", "Guzman", "804-555-9066"); friends[7] = new Contact("Marsha", "Grant", "243-555-2837"); Sorting.selectionSort(friends); for (Contact friend : friends) System.out.println(friend); }}```**Explanation of Code:**This Java program defines a `PhoneList` class, which contains a `main` method to execute the program. The program creates an array of `Contact` objects called `friends`, with a length of 8. Each element of this array is a new `Contact` object initialized with a first name, last name, and phone number. After populating the `friends` array, the program calls a method `Sorting.selectionSort(friends)`, which presumably sorts the array using selection sort (the implementation of this method is not provided in the snippet).Finally, the program iterates over each `Contact` object in the `friends` array and prints it to the system output. This likely involves calling a `toString` method on each `Contact` object, defined elsewhere in the code.

Answered: public class PhoneList { public static…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Modify the Contact class in Chapter 10 so that the sorting methods invoked in PhoneList.java keeps the Contact objects sorted by phone number.

```java
public class PhoneList {
public static void main (String[] args) {
Contact[] friends = new Contact[8];

friends[0] = new Contact("John", "Smith", "610-555-7384");
friends[1] = new Contact("Sarah", "Barnes", "215-555-3827");
friends[2] = new Contact("Mark", "Riley", "733-555-2969");
friends[3] = new Contact("Laura", "Getz", "663-555-3984");
friends[4] = new Contact("Larry", "Smith", "464-555-3489");
friends[5] = new Contact("Frank", "Phelps", "322-555-2284");
friends[6] = new Contact("Mario", "Guzman", "804-555-9066");
friends[7] = new Contact("Marsha", "Grant", "243-555-2837");

Sorting.selectionSort(friends);

for (Contact friend : friends)
System.out.println(friend);
}
}
```

**Explanation of Code:**

This Java program defines a `PhoneList` class, which contains a `main` method to execute the program. The program creates an array of `Contact` objects called `friends`, with a length of 8. Each element of this array is a new `Contact` object initialized with a first name, last name, and phone number.

After populating the `friends` array, the program calls a method `Sorting.selectionSort(friends)`, which presumably sorts the array using selection sort (the implementation of this method is not provided in the snippet).

Finally, the program iterates over each `Contact` object in the `friends` array and prints it to the system output. This likely involves calling a `toString` method on each `Contact` object, defined elsewhere in the code.

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Step 1

To compare two String objects, use the compareTo method on a String object For example The function compareTo compares "apple" and "cat" alphabetically and outputs the result as an integer.

If "apple" appears before "cat" in the alphabet, the compareTo method returns a negative number as a result.
If "apple" and "cat" are the same in alphabetical order, the compareTo function returns zero.
If "apple" follows "cat" alphabetically, the compareTo function gives a positive number.

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