public class A extends C { public void method1() { System.out.print("a1 "); } public String toString() { return "a"; } } public class B extends D { public void method2() { System.out.print("b2 "); } } public class C extends D { public void method1() { System.out.print("c1 "); } } public class D { public String toString() { return "d"; } public void method1() { System.out.print("d1 "); } public void method2() { System.out.print("d2 "); } } Consider the following code fragment: D[] elements = {new B(), new A(), new D(), new C()}; for (int i = 0; i < elements.length; i++) { System.out.print (elements [i] + " "); elements [i].method1(); elements [i].method2(); System.out.println(); // part 1 // part 2 // part 3 } Note that one iteration of this loop prints on its own line with each of the three parts separated by a single space. elements[0] - B(): elements[1] -A(): elements[2] - DO:
public class A extends C { public void method1() { System.out.print("a1 "); } public String toString() { return "a"; } } public class B extends D { public void method2() { System.out.print("b2 "); } } public class C extends D { public void method1() { System.out.print("c1 "); } } public class D { public String toString() { return "d"; } public void method1() { System.out.print("d1 "); } public void method2() { System.out.print("d2 "); } } Consider the following code fragment: D[] elements = {new B(), new A(), new D(), new C()}; for (int i = 0; i < elements.length; i++) { System.out.print (elements [i] + " "); elements [i].method1(); elements [i].method2(); System.out.println(); // part 1 // part 2 // part 3 } Note that one iteration of this loop prints on its own line with each of the three parts separated by a single space. elements[0] - B(): elements[1] -A(): elements[2] - DO:
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
![public class A extends C {
public void method1() { System.out.print("al "); }
public String toString() { return "a"; }
}
public class B extends D {
public void method2() { System.out.print("b2 "); }
}
public class C extends D {
public void method1() { System.out.print("c1 "); }
}
public class D {
public String toString() { return "d"; }
public void method1() { System.out.print("d1 "); }
public void method2() { System.out.print("d2 "); }
}
Consider the following code fragment:
D[] elements (new B(), new A(), new D(), new C()};
for (int i = 0; i < elements.length; i++) {
System.out.print (elements [i] + " ");
elements [i].method1();
// part 1
// part 2
// part 3
elements [i].method2();
System.out.println();
}
Note that one iteration of this loop prints on its own line with each of the three parts separated by
a single space.
elements[0] - B():
elements[1] - A():
elements[2] - D():](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b16e658-a030-43d8-b8a8-e7db675d8124%2Fecc222c8-3f19-49de-b08a-b30bad92395f%2Flirn3n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:public class A extends C {
public void method1() { System.out.print("al "); }
public String toString() { return "a"; }
}
public class B extends D {
public void method2() { System.out.print("b2 "); }
}
public class C extends D {
public void method1() { System.out.print("c1 "); }
}
public class D {
public String toString() { return "d"; }
public void method1() { System.out.print("d1 "); }
public void method2() { System.out.print("d2 "); }
}
Consider the following code fragment:
D[] elements (new B(), new A(), new D(), new C()};
for (int i = 0; i < elements.length; i++) {
System.out.print (elements [i] + " ");
elements [i].method1();
// part 1
// part 2
// part 3
elements [i].method2();
System.out.println();
}
Note that one iteration of this loop prints on its own line with each of the three parts separated by
a single space.
elements[0] - B():
elements[1] - A():
elements[2] - D():
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