PS Three Coplanar Charges Figure 2 F (net) F(1,3) F (2,3) Figure 1 4 m q2 - -3C q3 - +5C 3 m qi - +3C Three coplanar charges are positioned relative to one another as shown in Figure 1. The imaginary line that joins q1 and q2 is perpendicular to the imaginary line that joins q2 and q3. q2 is negative and that q1 and q3 are positive thus q1 repels (push) q3 and that q2 attracts (pulls) q3. Determine the following: The attractive electric force that exists between The repulsive electric force that exists between q2 and q3, F(2,3) q1 and q3, F(1,3) The net electric force F(net) that acts on q3 due to q1 and q2 as shown in figure 2. Use cosine law.

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Chapter1: Units, Trigonometry. And Vectors
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PS Three Coplanar Charges
Figure 2
F (net)
E(1,3)
F (2,3)
q3
Figure 1
4 m
q2 = -3 C
93 - +5C
3 m
qi = +3 C
Three coplanar charges are positioned relative to one another as shown in Figure 1. The imaginary line that joins
q1 and q2 is perpendicular to the imaginary line that joins q2 and q3. q2 is negative and that q1 and q3 are
positive thus q1 repels (push) q3 and that q2 attracts (pulls) q3.
Determine the following:
The attractive electric force that exists between
The repulsive electric force that exists between
q2 and q3, F(2,3)
q1 and q3, F(1,3)
The net electric force Finer) that acts on q3 due to g1 and g2 as shown in figure 2. Use cosine law.
Transcribed Image Text:PS Three Coplanar Charges Figure 2 F (net) E(1,3) F (2,3) q3 Figure 1 4 m q2 = -3 C 93 - +5C 3 m qi = +3 C Three coplanar charges are positioned relative to one another as shown in Figure 1. The imaginary line that joins q1 and q2 is perpendicular to the imaginary line that joins q2 and q3. q2 is negative and that q1 and q3 are positive thus q1 repels (push) q3 and that q2 attracts (pulls) q3. Determine the following: The attractive electric force that exists between The repulsive electric force that exists between q2 and q3, F(2,3) q1 and q3, F(1,3) The net electric force Finer) that acts on q3 due to g1 and g2 as shown in figure 2. Use cosine law.
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Hwo about the 5C? Why did it not change to negative? 

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Why did you use q2 as positive 3 instead of negative given that the original value of it is negative

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