A sample of birth weights of 48 girls was taken. Below are theresults (in g):2724.53340.13243.63442.12996.9304235053161.84022.83362.93768.92951.93229.72997.53758.13350.23210.73684.33530.13132.72776.93492.72655.13790.93064.63744.63294.52654.73536.62781.13756.33531.53654.23505.14018.630383202.330063701.63451.42986.53541.23232.9296631863550.33056.63467.1x = 3314.6 gs = 347.35 gUse a 5% significance level to test the claim that thestandard deviation of birth weights of girls is less than thestandard deviation of birth weights of boys, which is 530 g.Round all answers to 3 decimal places if possible. Step 4. Testing Procedure:Provide the critical value(s) for the Rejection Region.For a one-tailed test, use DNE for the unneededcritical value.• Left CV =• Right CV =%3DThe p-value isLink to Chi-Square Table:https://www.itl.nist.gov/div898/handbook/eda/section3/edaStep 5. DecisionIs the test statistic in the rejection region? ?Is the p-value less than the significance level? ?Conclusion:Select an answerStep 6. Interpretation:At a 5% significance level we Select an answerhavesufficient evidence to reject the null hypothesis infavor of the alternative hypothesis.<>

For the given data perform one variance chi square test

Answered: Provide the critical value(s) for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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*PLEASE show in excel A different investigator conducts a second study to investigate whether there is a difference in mean PEF in children with chronic bronchitis as compared to those without. Data on PEF are collected and summarized below. Based on the data, is there statistical evidence of a lower mean PEF in children with chronic bronchitis as compared to those without? Run the appropriate test at a=0.05. Group Number of Children Mean PEF Std Dev PEF Chronic Bronchitis 25 281 68 No Chronic Bronchitis 25 319 74 Step 1. Set up hypotheses and determine level of significance. Ho: H1: alpha: Step 2. Select the appropriate test statistic and give its formula. Step 3. Set up decision rule. Step 4. Compute the test statistic Step 5. Conclusion.
Use the 1odwing Wildlife: Coyotes A random sample of 46 adult coyotes in a region of northern Minnesota showed the average age to be z = 2.05 years, with sample standard deviation 8 = 0.82 years (based on information from the book Coyotes: Biology, Behavior and Management by M. Bekoff, Academic Press). However, it is thought that the overall population mean age of coyotes is µ=1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use a = 0.01. Fl in the blanks a 007 • Ho u- 175 years * H u> 176 yean QUESTION 7 What is your test statistic? (t-statistic) 2.48 QUESTION 8 What is your p-value? (Hint You will need the degrees of freedom to find the p-value.) <0.01d QUESTION 9 Do you reject the null hypothesis? O Yes No
This research was conducted with Korean adolescents in the Los Angeles area. Would you be willing to generalize the results of this study to Korean adolescents who live in other regions of the country? Why or why not.
The p-value for a t-statistic was .008. What is the best way to report the level of significance? p<.008 p<.05 p<.01 p<.001
What is the value of the test statistic? Find the p-value What is the appropriate conclusion at α=0.10? do not round please
if your data is not normally distributed, to describe dispersion you should use: O standard deviations O standard deviations based on a median quartiles O modes
Also write an interpretation for both images
Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…
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Fill in the Blanks Type your answers in all of the blanks and submit 11. Perform the following.05 level test: Ho: u = 20.4 vs. Ha: µ < 20.4, given a sample of 10 pieces of data had a mean of 18.8 and a standard deviation of 3.4. What is your data value (test statistic) to 3-decimal places? Type your answer here Write out the exact same data value again to 3-decimal places. Type your answer here What is your chart number (that seperates Reject and Fail to Reject)? Type your answer here 8. MacBook Air
Students measured the concentration of HCI in a solution by titrating with different indicators to find the end point. Mean HCl concentration (M) Number of Indicator (t standard deviation) 0.095650.00225 measurements A. Bromothymol blue B. Methyl red C. Bromocresol green SOURCE: Data from D. T. Harvey, "Statistical Evaluation of Acid-Base Indicators,"J. Chem. Ed, 28 0.08686+ 0.00098 18 0.08641 0.00113 29 1991, 68, 329, Is the difference between indicators B and C significant at the 95% confidence level? Use the F-test to determine whether the standard deviations of the HCl concentrations determined using indicators B and C are significantly different at the 95% confidence level. Report the calculated F value and the F value from the table. Fe= 0.7521 Incorrect Fuhle = 2.50
It is the most widely used and most reliable average when the data contains no extreme values. Choose MEDIAN the so MODE MEAN DEVIATION VARIANCE RANGE STANDARD DEVIATION STATISTICS MEAN

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