Prove the identity. 5 tan(3x) = 15 tan(x) – 5 tan²(x) 1- 3 tan?(x) Rewrite 3x as 2x + x and use the Addition Formula for Tangent to simplify. 5 tan(3x) = 5 tan(2x + x) 1- tan(2x) tan(x) Use the Double-Angle Formula for Tangent to simplify. + 5 tan(x) ctan(x)) 19 + 10 tan(x) (1 – tan (x)) – Need Help? Read It Watch It

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Prove the identity.**

\[ 5 \tan(3x) = \frac{15 \tan(x) - 5 \tan^3(x)}{1 - 3 \tan^2(x)} \]

Rewrite \(3x\) as \(2x + x\) and use the Addition Formula for Tangent to simplify.

\[ 5 \tan(3x) = 5 \left( \frac{\tan(2x + x)}{1 - \tan(2x) \tan(x)} \right) \]

Use the Double-Angle Formula for Tangent to simplify.

\[ = \frac{\_ \ + \ 5 \tan(x)}{1 - \left( \_ \right)\tan(x)} \]

\[ = \frac{\_ \ + 10 \tan(x)}{(1 - \tan^2(x)) \_} \]

\[ = \_ \]

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Transcribed Image Text:**Prove the identity.** \[ 5 \tan(3x) = \frac{15 \tan(x) - 5 \tan^3(x)}{1 - 3 \tan^2(x)} \] Rewrite \(3x\) as \(2x + x\) and use the Addition Formula for Tangent to simplify. \[ 5 \tan(3x) = 5 \left( \frac{\tan(2x + x)}{1 - \tan(2x) \tan(x)} \right) \] Use the Double-Angle Formula for Tangent to simplify. \[ = \frac{\_ \ + \ 5 \tan(x)}{1 - \left( \_ \right)\tan(x)} \] \[ = \frac{\_ \ + 10 \tan(x)}{(1 - \tan^2(x)) \_} \] \[ = \_ \] **Need Help?** Buttons: [Read It] [Watch It]
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