Prove that there is no simple group of order 315 = 32 .5 . 7.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Prove that there is no simple group of order 315 = 32 .5 . 7.
Expert Solution
Step 1: Given Information:
It has to be proved that there is no simple group of order .
Step 2: Calculation:
Consider an abelian -subgroup of order .
Assume, is the Sylow -subgroup of .
If , the number of -Sylow subgroup of is however
.
Hence, is normal in and it is unique.
And again, consider an abelian-subgroup of order .
Assume, is the Sylow subgroup of .
Similarly, must be normal in and it is unique.
Therefore, is abelian.
So,
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