6. Let G be a group of order p², where p is a prime. Show that G must have a subgroup of order p.

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**Problem 6: Subgroup Existence in Prime Squared Order Groups**

Let \( G \) be a group of order \( p^2 \), where \( p \) is a prime. Show that \( G \) must have a subgroup of order \( p \).

**Detailed Explanation:**

This problem is a classic application of group theory focusing on the existence of subgroups within finite groups whose order is a power of a prime. According to Sylow's theorems, every group \( G \) of order \( p^n \) has a nontrivial subgroup of order \( p^k \) for each \( k \) satisfying \( 0 \leq k \leq n \). Consequently, this implies that any group of order \( p^2 \) necessarily contains at least one subgroup of order \( p \). The problem asks you to demonstrate that such a subgroup must exist, leveraging foundational principles from abstract algebra.
Transcribed Image Text:**Problem 6: Subgroup Existence in Prime Squared Order Groups** Let \( G \) be a group of order \( p^2 \), where \( p \) is a prime. Show that \( G \) must have a subgroup of order \( p \). **Detailed Explanation:** This problem is a classic application of group theory focusing on the existence of subgroups within finite groups whose order is a power of a prime. According to Sylow's theorems, every group \( G \) of order \( p^n \) has a nontrivial subgroup of order \( p^k \) for each \( k \) satisfying \( 0 \leq k \leq n \). Consequently, this implies that any group of order \( p^2 \) necessarily contains at least one subgroup of order \( p \). The problem asks you to demonstrate that such a subgroup must exist, leveraging foundational principles from abstract algebra.
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