Prove that the force generated (per unit depth), F, by a pinnate muscle arrangement is F = 2fl sin æ cos a (8.26) where f is the force generated per unit cross-sectional muscle area, I is the pinnate segment length, and a is the muscle fiber angle.

Prove that the force generated (per unit depth), F, by a pinnate muscle arrangement is F = 2fl sin æ cos a (8.26) where f is the force generated per unit cross-sectional muscle area, I is the pinnate segment length, and a is the muscle fiber angle.

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter2: Vectors

Section: Chapter Questions

Problem 87AP: Show that (BC)A is the volume of the parallelepiped, with edges formed by the three vectors in the...

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