A mass spectrometer is a device that can sort ions based on their mass to charge ratio. incoming ions V q ion detector B Given the incoming particle is a proton with a horizontal speed of 1.4x108 m/s, and the magnetic field strength is 0.7 T, what would the radius of the proton's path be, in meters?
A mass spectrometer is a device that can sort ions based on their mass to charge ratio. incoming ions V q ion detector B Given the incoming particle is a proton with a horizontal speed of 1.4x108 m/s, and the magnetic field strength is 0.7 T, what would the radius of the proton's path be, in meters?
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter26: Electromagnetism
Section: Chapter Questions
Problem 64A
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![A mass spectrometer is a device that can sort ions based on their mass to charge
ratio.
incoming
ions
q
V
ion
detector
B
Given the incoming particle is a proton with a horizontal speed of 1.4x108 m/s, and
the magnetic field strength is 0.7 T, what would the radius of the proton's path be, in
meters?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F911021fb-3b0f-48c3-8c15-6035ca56e0d3%2F4822f2d8-7949-4705-9c13-93c2ab1064ea%2Fxme9ksb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A mass spectrometer is a device that can sort ions based on their mass to charge
ratio.
incoming
ions
q
V
ion
detector
B
Given the incoming particle is a proton with a horizontal speed of 1.4x108 m/s, and
the magnetic field strength is 0.7 T, what would the radius of the proton's path be, in
meters?
![Given data
- V=1.4x108 m/s
- B = 0.7 T
Solution:
In equilibrium.
FB
qvB
r
=
Fe
my ²
mv
2 B
Putting all values.
in
r = 2.1 m
mv
2B
(24.
r = (1.67 x 10-27 kg) (1.4 x 108 m/s)
(1.602x10-¹) (0.7T)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F911021fb-3b0f-48c3-8c15-6035ca56e0d3%2F4822f2d8-7949-4705-9c13-93c2ab1064ea%2F0oxygxm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given data
- V=1.4x108 m/s
- B = 0.7 T
Solution:
In equilibrium.
FB
qvB
r
=
Fe
my ²
mv
2 B
Putting all values.
in
r = 2.1 m
mv
2B
(24.
r = (1.67 x 10-27 kg) (1.4 x 108 m/s)
(1.602x10-¹) (0.7T)
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