Prove that average reduces Variance
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Prove that average reduces Variance
Hint:
The average is the mean of all observations. It gives the central value of the data.
The variance measures the spread of data.
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Solved in 2 steps
- One difference between ANOVA and regression is: a) ANOVA is for statistical inference, whereas regression is not b) a regression line accounts for variability, whereas variability is not a concept in ANOVA c) in regression, we estimate a slope, whereas in ANOVA, we estimate mean differences d) ANOVA bases its inferences on samples, whereas regression bases its inferences on populations e) ANOVA and regression are not different at all, they are exactly the same f) ANOVA features p-values, whereas regression does notTwo groups of mice were injected with a measured amount of tumor pulp. The first group of 27 mice was given a high dosage of chemotherapy while the second group of 30 mice was given a low dosage of chemotherapy. After forty days, the first group had an average tumor size of 0.51cc with a variance of 0.10; the second group had an average tumor size of 0.64cc with a variance of 0.045. Were the tumor sizes of group 1 significantly smaller than those of group 2? What is the observed test statistic?Which of the following is true of fixed effect estimators A. The fixed effects estimator is equal to the instrumental variable estimator if R^2 is equal to 1. B. The fixed effects estimators are biased if the regression model exhibits multicollinearity. C. The fixed effects estimators have lower variance than the ordinary least squares estimators. D. The fixed effects estimators have large standard errors when R^2 lies close to 0.
- A least squares line for a sample with 11 observations has an SSE = 192; calculate and s. Please show your work So i can understand how you arrived at the answerA set of solar batteries is used in a research satellite. The satellite can run on only one battery, but it runs best if more than one battery is used. The variance σ2 of lifetimes of these batteries affects the useful lifetime of the satellite before it goes dead. If the variance is too small, all the batteries will tend to die at once. Why? If the variance is too large, the batteries are simply not dependable. Why? Engineers have determined that a variance of σ2 = 23 months (squared) is most desirable for these batteries. A random sample of 22 batteries gave a sample variance of 13.2 months (squared). Using a 0.05 level of significance, test the claim that σ2 = 23 against the claim that σ2 is different from 23. (a) What is the level of significance? Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.) What are the degrees of freedom? (f) Find a 90% confidence interval for the population variance. (Round your answers to two decimal…Which one of the following assumptions is required for the 2SLS estimator to be consistent? a) There are perfect linear relationships among the instrumental variables b) There is a correlation between each instrumental variable and the endogenous variable c) The conditional variance of the error term depends on an exogenous explanatory variable d) There is a strong correlation between each instrumental variable and the error term
- A set of solar batteries is used in a research satellite. The satellite can run on only one battery, but it runs best if more than one battery is used. The variance σ2 of lifetimes of these batteries affects the useful lifetime of the satellite before it goes dead. If the variance is too small, all the batteries will tend to die at once. Why? If the variance is too large, the batteries are simply not dependable. Why? Engineers have determined that a variance of σ2 = 23 months (squared) is most desirable for these batteries. A random sample of 20 batteries gave a sample variance of 13.8 months (squared). Using a 0.05 level of significance, test the claim that σ2 = 23 against the claim that σ2 is different from 23. (a) What is the level of significance?State the null and alternate hypotheses. A. Ho: σ2 = 23; H1: σ2 ≠ 23 B. Ho: σ2 = 23; H1: σ2 < 23 C. Ho: σ2 = 23; H1: σ2 > 23 D. Ho: σ2 > 23; H1: σ2 = 23 (b) Find the value of the chi-square statistic for the sample. (Round…If I was calculating the variance of this list of numbers (attached), do I need to include the "no home games" as a 0 and base the calculation on 14 entries? Or do I just leave them out completely and base the calculation on 12 entries?The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B ( group 2). A random sample of 17 rats was selected from group 1and 11 rats from group 2, Then their weight were recorded. The results are shown in the following table 2 J غير مجاب عليه بعد الدرجة من 0 2.0 sd Median Mean n 3.0 3.5 17 group 1 2.0 2.20 11 group 2 علم هذا السؤال 1.05 1.15 F19,16,0.025 =0.386 F15,12,0.05 =0.404 F16,10,0.025=0.335 F19.16,0.05 =0.451 F15,12,0.1=0.496 F1610,0.05=0.401 F16,19,0.025 =0.371 F1215,0.05 =0.382 F10,16,0.025 =0.286 F16,19,0.05 =0.437 F1215,0.1=0.475 F10,16,0.05=0.354 Construct a 95% confidence interval for the ratio of the variances. [ Write only the final result in the box below ] 直 a
- A manufacturing company is interested in buying one of two different kinds of machines for production purposes. The first machine was run for 20 hours. It produces on average of 40 items per hour with variance of 8 items2. The second machine was run for 15 hours. It produces on average 50 items per hour with variance of 10 items2. Assume that the production per hour for each machine is (approximately) normally distributed and there a homogeneity between the populations' variances of the number of items produced by the 2 machines Compute 90% confidence interval for the difference between the two means. What is the tabulated value What is the S.E value What Is the lower and upper boundThe built-in data set, rock, is a data frame recording the measurements of rock sample from a petroleum reservoir. We are interested in the area column of rock. Using R we can convert this column into the vector x by the assignment x30 we can create a confidence interval for μ using a normal critical value. If we want the confidence interval to be at the 94% level and we use a normal critical value, then what critical value should we use? i) Calculate a 94% confidence interval(using a normal critical value) for μ.Identify which of the following scatterplots contain possible outliers or observations influential for the least squares regression line. Select all that apply 100- 90- 80- 을 70어 3 60- 50- 40- 25 20- 20 15 - 10- 5 10 15 20 25 30 35 40 45 50 20,000 40,000 60,000 80,000 100,000 120,000 Number of incorrect answers Distance driven (mi) Age (years) Outlier Influential observation Outlier 70 24– 50- 65 60 - 22- 40- 55 - 20-. 8 30- 50 – 18- 20- 45 65 70 75 80 5.0 5.5 6.0 6.5 7.0 7.5 8.0 2.05 2.10 2.15 2.20 2.25 2.30 2.35 2.40 Daily high temperature (°F) Price of gasoline ($/gal) Hours slept Influential observation No outliers or influential observations Outlier Answer Bank Influential observation Outlier No outliers or influential observations Daily low temperature (°F) Duration of commute (min) Years of full-time employment Number of oil changes (zo) pəwnsuoɔ əəyoɔ