Prove that: [(Â×B)×Ĉ]×Ď+[(Â×Â)×Ď]×¢ +[(Ĉ×Ď) D
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![Prove that:
[(Â× B)×Ĉ]×Ď + [(Â × Â)× Ď]×Č +[(Ĉ×Ď)× Â]× Â + [(Ď×Č) ×B] × Â = 0
с
B
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