Prove that: [(Â×B)×Ĉ]×Ď+[(Â×Â)×Ď]×¢ +[(Ĉ×Ď) D
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![Prove that:
[(Â× B)×Ĉ]×Ď + [(Â × Â)× Ď]×Č +[(Ĉ×Ď)× Â]× Â + [(Ď×Č) ×B] × Â = 0
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B
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- Vector B→B→ has magnitude 7.30 and direction 14.0° below the +x-axis. Vector C→C→ has x-component Cx = −2.00 and y-component Cy = −6.70. f. What angle does the resultant vector C→+B→C→+B→ make with the +x-axis in clockwise direction? A positive angle is counterclockwise from the +x-axis. answer in degrees g. What is the magnitude of C→−B→C→-B→ ? h. What angle does the vector C→−B→C→-B→ make with the +x-axis in counterclockwise direction? A positive angle is counterclockwise from the +x-axis. i. What is the x-component of C→−B→C→-B→ ? j. What is the y-component of C→−B→C→-B→ ?Find the number of significant figures in each of the following. (a) 61.8 ± 0.3 (b) 3.86 ✕ 109 (c) 2.80000 ✕ 10−6 (d) 0.00451.48 The angle between two vectors is 0. (a) If 0 = 30.0°, which has the greater magnitude: the scalar product or the vector product of the two vectors? (b) For what value (or values) of are the magnitudes of the scalar product and the vector product equal?