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Proposition: If m is an odd integer, then m + 6 is an odd integer. Proof: For m + 6 to be an odd integer, there must exist an integer n such that m+6=2n+1. Subtracting 6 from both sides, we see that m = 2n+1-6 = = 2n― 6+1 = 2(n − 3) + 1. Since the integers are closed under subtraction, then n-3 € Z. Hence, the last equation implies that m = = 2q+1 where q = n = 3. This proves - that if m is an odd integer, then m + 6 is an odd integer. Based upon the Reading assignment and the Elements of Style >>, which of the following is the most significant error in the proof? The proof does not use complete sentences The proof contains a sentence that begins with a mathematical symbol The proof uses cumbersome notation The proof contains a variable used for more than one object The proof is written backwards The proof uses an example to prove the general case

Proposition: If m is an odd integer, then m + 6 is an odd integer. Proof: For m + 6 to be an odd integer, there must exist an integer n such that m+6=2n+1. Subtracting 6 from both sides, we see that m = 2n+1-6 = = 2n― 6+1 = 2(n − 3) + 1. Since the integers are closed under subtraction, then n-3 € Z. Hence, the last equation implies that m = = 2q+1 where q = n = 3. This proves - that if m is an odd integer, then m + 6 is an odd integer. Based upon the Reading assignment and the Elements of Style >>, which of the following is the most significant error in the proof? The proof does not use complete sentences The proof contains a sentence that begins with a mathematical symbol The proof uses cumbersome notation The proof contains a variable used for more than one object The proof is written backwards The proof uses an example to prove the general case

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 39E
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Proposition: If m is an odd integer, then m + 6 is an odd integer. Proof: For m + 6 to be an odd integer, there must exist an integer n such that m+6=2n+1. Subtracting 6 from both sides, we see that m = 2n+1-6 = = 2n― 6+1 = 2(n − 3) + 1. Since the integers are closed under subtraction, then n-3 € Z. Hence, the last equation implies that m = = 2q+1 where q = n = 3. This proves - that if m is an odd integer, then m + 6 is an odd integer. Based upon the Reading assignment and the Elements of Style >>, which of the following is the most significant error in the proof? The proof does not use complete sentences The proof contains a sentence that begins with a mathematical symbol The proof uses cumbersome notation The proof contains a variable used for more than one object The proof is written backwards The proof uses an example to prove the general case
Transcribed Image Text:Proposition: If m is an odd integer, then m + 6 is an odd integer. Proof: For m + 6 to be an odd integer, there must exist an integer n such that m+6=2n+1. Subtracting 6 from both sides, we see that m = 2n+1-6 = = 2n― 6+1 = 2(n − 3) + 1. Since the integers are closed under subtraction, then n-3 € Z. Hence, the last equation implies that m = = 2q+1 where q = n = 3. This proves - that if m is an odd integer, then m + 6 is an odd integer. Based upon the Reading assignment and the Elements of Style >>, which of the following is the most significant error in the proof? The proof does not use complete sentences The proof contains a sentence that begins with a mathematical symbol The proof uses cumbersome notation The proof contains a variable used for more than one object The proof is written backwards The proof uses an example to prove the general case
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