Proposition 4.4.6. A subset A of a metric space S is closed if and only if A' C A. When we considered the set A = (0,1) in R, we observed that A' = [0, 1). Clearly A' is not contained in A, thus by Proposition 4.4.6, A = (0, 1) is not closed. For a, b €R with a
Proposition 4.4.6. A subset A of a metric space S is closed if and only if A' C A. When we considered the set A = (0,1) in R, we observed that A' = [0, 1). Clearly A' is not contained in A, thus by Proposition 4.4.6, A = (0, 1) is not closed. For a, b €R with a
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Proposition 4.4.6.** A subset \( A \) of a metric space \( S \) is closed if and only if \( A' \subseteq A \).
When we considered the set \( A = (0, 1) \) in \( \mathbb{R} \), we observed that \( A' = [0, 1] \). Clearly \( A' \) is not contained in \( A \), thus by Proposition 4.4.6, \( A = (0, 1) \) is not closed.
*For \( a, b \in \mathbb{R} \) with \( a < b \), is \( (a, b] \) closed? Explain by appealing to Proposition 4.4.6.*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45ccc3c2-853e-4ee6-91f9-7e4723419012%2Fa4a92945-d050-471a-8943-c292817a25a7%2F3kxsrr8_processed.png&w=3840&q=75)
Transcribed Image Text:**Proposition 4.4.6.** A subset \( A \) of a metric space \( S \) is closed if and only if \( A' \subseteq A \).
When we considered the set \( A = (0, 1) \) in \( \mathbb{R} \), we observed that \( A' = [0, 1] \). Clearly \( A' \) is not contained in \( A \), thus by Proposition 4.4.6, \( A = (0, 1) \) is not closed.
*For \( a, b \in \mathbb{R} \) with \( a < b \), is \( (a, b] \) closed? Explain by appealing to Proposition 4.4.6.*
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