Proportional Relationships in Chemical Reactions A chemist runs three trials of an experiment to produce ammonia (NH3) from nitrogen (N₂) and hydrogen (H₂). The unbalanced equation is I N₂ + H₂ ->> NH3 The chemist places different amounts of the reactants in a reaction vessel, adjusts some of the conditions such as pressure and temperature, and then records the amounts of the reactants and the products in the table. Amount of Products and Reactants for N₂ + H₂ → NH3 Trial Original amount (mol) Final amount (mol) Change in amount (mol) H₂ NH3 N₂ H₂ NH3 N₂ H₂ NH3 N₂ 0.345 0.345 0.000 1 0.335 0.315 0.020 2 0.102 0.345 0.000 0.032 0.135 0.140 3 0.345 0.298 0.000 0.305 0.178 0.080 1. SEP Use Mathematics Calculate (in moles) the amount of each reactant that was used up in the reaction and the amount of product that was produced. Record your answers in the table.

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### Proportional Relationships in Chemical Reactions

A chemist runs three trials of an experiment to produce ammonia (NH₃) from nitrogen (N₂) and hydrogen (H₂). The unbalanced equation is:

\[ \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \]

The chemist places different amounts of the reactants in a reaction vessel, adjusts some of the conditions such as pressure and temperature, and then records the amounts of the reactants and the products in the table below.

#### Amounts of Products and Reactants for \( \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \)

| Trial | Original amount (mol) | Final amount (mol) | Change in amount (mol) |
|-------|------------------------|--------------------|------------------------|
|       | \(\text{N}_2\)   | \(\text{H}_2\)   | \(\text{NH}_3\)  | \(\text{N}_2\)   | \(\text{H}_2\)   | \(\text{NH}_3\)  | \(\text{N}_2\)   | \(\text{H}_2\)   | \(\text{NH}_3\)  |
| 1     | 0.345                  | 0.345              | 0.000                | 0.335                  | 0.315              | 0.020                |                        |                        |                        |
| 2     | 0.102                  | 0.345              | 0.000                | 0.032                  | 0.135              | 0.140                |                        |                        |                        |
| 3     | 0.345                  | 0.298              | 0.000                | 0.305                  | 0.178              | 0.080                |                        |                        |                        |

##### Task

1. **SEP Use Mathematics**: Calculate (in moles) the amount of each reactant that was used up in the reaction and the amount of product that was produced. Record your answers in the table.
Transcribed Image Text:### Proportional Relationships in Chemical Reactions A chemist runs three trials of an experiment to produce ammonia (NH₃) from nitrogen (N₂) and hydrogen (H₂). The unbalanced equation is: \[ \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \] The chemist places different amounts of the reactants in a reaction vessel, adjusts some of the conditions such as pressure and temperature, and then records the amounts of the reactants and the products in the table below. #### Amounts of Products and Reactants for \( \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \) | Trial | Original amount (mol) | Final amount (mol) | Change in amount (mol) | |-------|------------------------|--------------------|------------------------| | | \(\text{N}_2\) | \(\text{H}_2\) | \(\text{NH}_3\) | \(\text{N}_2\) | \(\text{H}_2\) | \(\text{NH}_3\) | \(\text{N}_2\) | \(\text{H}_2\) | \(\text{NH}_3\) | | 1 | 0.345 | 0.345 | 0.000 | 0.335 | 0.315 | 0.020 | | | | | 2 | 0.102 | 0.345 | 0.000 | 0.032 | 0.135 | 0.140 | | | | | 3 | 0.345 | 0.298 | 0.000 | 0.305 | 0.178 | 0.080 | | | | ##### Task 1. **SEP Use Mathematics**: Calculate (in moles) the amount of each reactant that was used up in the reaction and the amount of product that was produced. Record your answers in the table.
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