Propane is a hydrocarbon that fuels everything from gas grills to home furnaces. Below is the balanced chemical equation for the combustion of propane (C3H8): C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O If you have 410 grams of propane and want to know how many grams of oxygen are required to burn it, you can follow these steps… Find the number of moles of propane that you have, then convert grams to moles! (1 mol ÷ 44 g )×410 g = 9.32 mol of 5×.9.32 mol oxygen = 46.6 mol of oxygen The moles of propane are related to the moles of oxygen by the molar ratio (ratio of coefficients in the balanced chemical equation). Find the number of moles of oxygen you need to give the moles of propane from part 5a. 1 mol oxygen molecule = 32 g of oxygen 46.6 mol of oxygen = 32 g × 46.6 mol of oxygen = 1491.2 g of oxygen Find the grams of oxygen from the moles of oxygen. Convert the moles of oxygen (answer to part 5b) to grams of oxygen (O2)! Hint: use the molar mass for O2, not just O. You should get approximately 1490 g of oxygen. Answer the Last question.
Propane is a hydrocarbon that fuels everything from gas grills to home furnaces. Below is the balanced chemical equation for the combustion of propane (C3H8): C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O If you have 410 grams of propane and want to know how many grams of oxygen are required to burn it, you can follow these steps… Find the number of moles of propane that you have, then convert grams to moles! (1 mol ÷ 44 g )×410 g = 9.32 mol of 5×.9.32 mol oxygen = 46.6 mol of oxygen The moles of propane are related to the moles of oxygen by the molar ratio (ratio of coefficients in the balanced chemical equation). Find the number of moles of oxygen you need to give the moles of propane from part 5a. 1 mol oxygen molecule = 32 g of oxygen 46.6 mol of oxygen = 32 g × 46.6 mol of oxygen = 1491.2 g of oxygen Find the grams of oxygen from the moles of oxygen. Convert the moles of oxygen (answer to part 5b) to grams of oxygen (O2)! Hint: use the molar mass for O2, not just O. You should get approximately 1490 g of oxygen. Answer the Last question.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Propane is a hydrocarbon that fuels everything from gas grills to home furnaces. Below is the balanced chemical equation for the combustion of propane (C3H8):
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O
- If you have 410 grams of propane and want to know how many grams of oxygen are required to burn it, you can follow these steps…
- Find the number of moles of propane that you have, then convert grams to moles!
(1 mol ÷ 44 g )×410 g
= 9.32 mol of 5×.9.32 mol oxygen
= 46.6 mol of oxygen
- The moles of propane are related to the moles of oxygen by the molar ratio (ratio of coefficients in the balanced chemical equation). Find the number of moles of oxygen you need to give the moles of propane from part 5a.
1 mol oxygen molecule = 32 g of oxygen
46.6 mol of oxygen = 32 g × 46.6 mol of oxygen
= 1491.2 g of oxygen
- Find the grams of oxygen from the moles of oxygen. Convert the moles of oxygen (answer to part 5b) to grams of oxygen (O2)! Hint: use the molar mass for O2, not just O. You should get approximately 1490 g of oxygen.
Answer the Last question.
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