Propane C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 450 kJ of heat. C3H8(g) + 502(g) 3CO2(g) + 4 H2O(g) AH = - 2043 kJ ======> MW сзн8 = 44.1 g/mol

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Chapter1: Chemical Foundations
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Propane C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would
need to provide 450 kJ of heat.
C3H8(g) + 502(g)
3CO2(g) +4 H2O)
AH = - 2043 kJ
======>
MW
- 44.1 g/mol
%3D
C3H8
Transcribed Image Text:Propane C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 450 kJ of heat. C3H8(g) + 502(g) 3CO2(g) +4 H2O) AH = - 2043 kJ ======> MW - 44.1 g/mol %3D C3H8
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