Hydrogen cyanide (HCN) is prepared from ammonia (NH3) and natural gas (CH4) as shown in the equation below. How many grams of H₂O form when 1,413 kJ of heat is formed? 2NH3(g) + 302(g) + 2CH4 → 2HCN(g) + 6H₂O(g) AH = -939 kJ

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Chapter6: Thermochemisty
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Hydrogen cyanide (HCN) is prepared from ammonia (NH3) and natural gas (CH4) as shown in
the equation below. How many grams of H₂O form when 1,413 kJ of heat is formed?
2NH3(g) + 302(g) + 2CH4 → 2HCN(g) + 6H₂O(g)
ΔΗ = -939 kJ
Transcribed Image Text:Hydrogen cyanide (HCN) is prepared from ammonia (NH3) and natural gas (CH4) as shown in the equation below. How many grams of H₂O form when 1,413 kJ of heat is formed? 2NH3(g) + 302(g) + 2CH4 → 2HCN(g) + 6H₂O(g) ΔΗ = -939 kJ
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