program
8.28 LAB: Check if list is sorted
Write the in_order() function, which has a list of integers as a parameter, and returns True if the integers are sorted (in order from low to high) or False otherwise. The
Ex: If the list passed to the in_order() function is [5, 6, 7, 8, 3], then the function returns False and the program outputs:
Not in orderEx: If the list passed to the in_order() function is [5, 6, 7, 8, 10], then the function returns True and the program outputs:
In orderNote: Use a for loop. DO NOT use sorted() or sort().
this is the code im supposed to use
def in_order(nums):
# Type your code here.
if __name__ == '__main__':
# Test out-of-order example
nums1 = [5, 6, 7, 8, 3]
if in_order(nums1):
print('In order')
else:
print('Not in order')
# Test in-order example
nums2 = [5, 6, 7, 8, 10]
if in_order(nums2):
print('In order')
else:
print('Not in order')
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