products in this combustion reaction to determine the limiting reagent and the amount of the reactant in excess. Initial amounts of each reactant are given. C3H8 + 502 26.3 g 21.8 g + 3C02(g) + 4H₂O(l)

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21. Verify that it does not matter which product you use to predict the limiting reagent by using both
products in this combustion reaction to determine the limiting reagent and the amount of the reactant in
excess. Initial amounts of each reactant are given.
C3H8 + 502
26.3 g 21.8 g
1
3C0₂(g) + 4H₂O(l)
Transcribed Image Text:21. Verify that it does not matter which product you use to predict the limiting reagent by using both products in this combustion reaction to determine the limiting reagent and the amount of the reactant in excess. Initial amounts of each reactant are given. C3H8 + 502 26.3 g 21.8 g 1 3C0₂(g) + 4H₂O(l)
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We will determine the limiting reagent and the amount of the reactant in
excess. Initial amounts of each reactant are given.
C3H8 + 502 →3CO2(g) + 4H2O(l) 
26.3 g 21.8 g

mole = Given mass/ Molar mass

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