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Macmillan Learning Consider the reaction. 2 Pb(s) + O₂(g) An excess of oxygen reacts with 451.4 g of lead, forming 321.9 g of lead(II) oxide. Calculate the percent yield of the reaction. percent yield: 2 PbO(s) %

Macmillan Learning Consider the reaction. 2 Pb(s) + O₂(g) An excess of oxygen reacts with 451.4 g of lead, forming 321.9 g of lead(II) oxide. Calculate the percent yield of the reaction. percent yield: 2 PbO(s) %

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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An excess of oxygen reacts with 451.4 g of lead, forming 321.9 g of lead(I1) oxide. Calculate the percent yield of the reaction.
### Reaction Description **Chemical Reaction Equation:** \[ 2 \text{Pb(s)} + \text{O}_2\text{(g)} \rightarrow 2 \text{PbO(s)} \] **Context:** An excess of oxygen reacts with 451.4 g of lead, resulting in the formation of 321.9 g of lead(II) oxide. Your task is to calculate the percent yield of this reaction. **Calculation Task:** - Calculate the **percent yield** based on the given amounts of reactants and products. **Input:** - Percent yield: [Input box for answer] % This exercise involves stoichiometry and the calculation of percent yield, which is an important aspect of understanding the efficiency of chemical reactions.
Transcribed Image Text:### Reaction Description **Chemical Reaction Equation:** \[ 2 \text{Pb(s)} + \text{O}_2\text{(g)} \rightarrow 2 \text{PbO(s)} \] **Context:** An excess of oxygen reacts with 451.4 g of lead, resulting in the formation of 321.9 g of lead(II) oxide. Your task is to calculate the percent yield of this reaction. **Calculation Task:** - Calculate the **percent yield** based on the given amounts of reactants and products. **Input:** - Percent yield: [Input box for answer] % This exercise involves stoichiometry and the calculation of percent yield, which is an important aspect of understanding the efficiency of chemical reactions.
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