Procopio is driving a car (m = 1000 kg) at v1 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s =15 m before stopping completely. How much force F was needed to stop the car? The formula for the work done by the force F as the car traveled a distance s before stopping is: W = __ By the work-energy theorem: W = __ - K1 = -½2 __ __2 Combining these two equations for work and isolating F, we obtain an expression for F: F = __ __2/(__) Plugging in values, we know __ that 4.4 newtons of force is needed to stop the car.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Procopio is driving a car (m = 1000 kg) at v1 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s =15 m before stopping completely. How much force F was needed to stop the car?

The formula for the work done by the force F as the car traveled a distance s before stopping is:

W = __

By the work-energy theorem:

W = __ - K1 = -½__ __2

Combining these two equations for work and isolating F, we obtain an expression for F:

F = __ __2/(__)

Plugging in values, we know __ that 4.4 newtons of force is needed to stop the car.

QUESTION 4
Procopio is driving a car (m = 1000 kg) at v1 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s =
15 m before stopping completely. How much force Fwas needed to stop the car?
The formula for the work done by the force F as the car traveled a distance s before stopping is:
w = Fxs
By the work-energy theorem:
w = K2
- K1 = -2 mv
2
1
Combining these two equations for work and isolating F, we obtain an expression for F:
F= 1/2mv
12( s
Plugging in values, we know that -411
4.4 newtons of force is needed to stop the car.
Transcribed Image Text:QUESTION 4 Procopio is driving a car (m = 1000 kg) at v1 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car? The formula for the work done by the force F as the car traveled a distance s before stopping is: w = Fxs By the work-energy theorem: w = K2 - K1 = -2 mv 2 1 Combining these two equations for work and isolating F, we obtain an expression for F: F= 1/2mv 12( s Plugging in values, we know that -411 4.4 newtons of force is needed to stop the car.
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