Procopio is driving a car (m 1000 kg) at v = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force F was needed to stop the car? The formula for the work done by the force F as the car traveled a distance s before stopping is: W = Fs By the work-energy theorem: W = 0 2 K1 = -½ m Combining these two equations for work and isolating F, we obtain an expression for F: F = m v1 2 2s 4.4 newtons of force is needed to stop the car. Plugging in values vwe know that -411
Procopio is driving a car (m 1000 kg) at v = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force F was needed to stop the car? The formula for the work done by the force F as the car traveled a distance s before stopping is: W = Fs By the work-energy theorem: W = 0 2 K1 = -½ m Combining these two equations for work and isolating F, we obtain an expression for F: F = m v1 2 2s 4.4 newtons of force is needed to stop the car. Plugging in values vwe know that -411
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Procopio is driving a car (m = 1000 kg) at v = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping
completely. How much force Fwas needed to stop the car?
The formula for the work done by the force F as the car traveled a distance s before stopping is:
く、
W = Fs
2
By the work-energy theorem:
W = 0
v1
- K1 = -4
m
Combining these two equations for work and isolating F, we obtain an expression for F:
2 2s
v1
F = m
4.4 newtons of force is needed to stop the car.
Plugging in values, we know that -411,
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