Process 0: int rank = 0; int commsize = 4; for(int i = 1; i < commsize; i++) { } //receive a vector from process i if (//receive was successful) for (int j = 1; j < size OfVec; j++) cout << vec[i]<<""; Output: 123 246 369 Process 1: //send a vector of 1, 2, 3 to Process 0 Process 2: //send a vector of 2, 4, 6 to Process 0 Process 3: //send a vector of 3, 6, 9 to Process 0
Process 0: int rank = 0; int commsize = 4; for(int i = 1; i < commsize; i++) { } //receive a vector from process i if (//receive was successful) for (int j = 1; j < size OfVec; j++) cout << vec[i]<<""; Output: 123 246 369 Process 1: //send a vector of 1, 2, 3 to Process 0 Process 2: //send a vector of 2, 4, 6 to Process 0 Process 3: //send a vector of 3, 6, 9 to Process 0
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Topic Video
Question
For this MPI Times Table
• Process 0 will: Receive one vector of size N-1 from each of the other N-1 processes and output
their contents, starting with process 1 and ending with process N.
• Processes 1-N will: Send one vector of size N-1 to process 0 containing the first N-1 multiples of
its own process number.
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