Procedures: In a 25 mL roundbottom flask equipped with a stir bar, add 0.0010 mole(____mg, _mL; density = 1.08 g/mL) of 2-acetylpyridine and 10 mL of water. (Always work with 2-acetylpyridine in the hood. Strong odor-do you recognize it?) Stir the mixture vigorously. In a separate vial, dissolve 0.0010 mole (mg) nitrobenzaldehyde in a minimum amount of hot methanol. While still hot, add the solution of aldehyde into the vigorously stirring mixture in the roundbottom flask. Add 0.00025 mol (mg) of base (either sodium carbonate or sodium hydroxide) dissolved in 5 mL of water. Stir for one hour. (If heating, attach a reflux condenser to the reaction flask and heat in a hot water bath. Do not allow the water bath to exceed 65 °C.) Cool the reaction in an ice bath and collect the precipitate by suction filtration. Wash the solid with water (3x 10mL.)

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the attached procedure, write a general reaction scheme (not mechanism) that shows starting materials, an arrow with the words “basic conditions” over the arrow, and both possible products (addition and condensation). 

Your team of four will investigate two parameters: temperature and choice of base. You should run the
reaction at room temperature and 60 °C, and you should compare the reaction using sodium carbonate
to the reaction with sodium hydroxide. Based on your knowledge of the aldol reaction, you should have
a prediction of the expected product or products. After the reaction is complete, you should characterize
the resulting compound to determine its actual identity.
Procedures:
In a 25 mL roundbottom flask equipped with a stir bar, add 0.0010 mole ( mg, mL; density = 1.08
g/mL) of 2-acetylpyridine and 10 mL of water. (Always work with 2-acetylpyridine in the hood. Strong
odor-do you recognize it?) Stir the mixture vigorously. In a separate vial, dissolve 0.0010 mole (______mg)
nitrobenzaldehyde in a minimum amount of hot methanol. While still hot, add the solution of aldehyde
into the vigorously stirring mixture in the round bottom flask. Add 0.00025 mol (_______mg) of base (either
sodium carbonate or sodium hydroxide) dissolved in 5 mL of water. Stir for one hour. (If heating, attach
a reflux condenser to the reaction flask and heat in a hot water bath. Do not allow the water bath to
exceed 65 °C.) Cool the reaction in an ice bath and collect the precipitate by suction filtration. Wash the
solid with water (3x 10mL.)
Transcribed Image Text:Your team of four will investigate two parameters: temperature and choice of base. You should run the reaction at room temperature and 60 °C, and you should compare the reaction using sodium carbonate to the reaction with sodium hydroxide. Based on your knowledge of the aldol reaction, you should have a prediction of the expected product or products. After the reaction is complete, you should characterize the resulting compound to determine its actual identity. Procedures: In a 25 mL roundbottom flask equipped with a stir bar, add 0.0010 mole ( mg, mL; density = 1.08 g/mL) of 2-acetylpyridine and 10 mL of water. (Always work with 2-acetylpyridine in the hood. Strong odor-do you recognize it?) Stir the mixture vigorously. In a separate vial, dissolve 0.0010 mole (______mg) nitrobenzaldehyde in a minimum amount of hot methanol. While still hot, add the solution of aldehyde into the vigorously stirring mixture in the round bottom flask. Add 0.00025 mol (_______mg) of base (either sodium carbonate or sodium hydroxide) dissolved in 5 mL of water. Stir for one hour. (If heating, attach a reflux condenser to the reaction flask and heat in a hot water bath. Do not allow the water bath to exceed 65 °C.) Cool the reaction in an ice bath and collect the precipitate by suction filtration. Wash the solid with water (3x 10mL.)
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