PROBLEMS 1)25.00 mL of 0.100 M HCl solution is titrated with a 0.1 M NAOH solution. What is the pH's on the addition of the following strong base. a-) initially (Before adding NaOH) b-) Before the equivalence point (with the addition of 24.00 mL of 0.100 M NaOH) c-) At the equivalence point (with the addition of 25.00 mL of 0.100 M NAOH) d-) After the equivalence point(with the addition of 26.00 mL of 0.100 M NAOH) 0.025L nHt=0.0025nol HCISH4Cに *Al。t に

PROBLEMS 1)25.00 mL of 0.100 M HCl solution is titrated with a 0.1 M NAOH solution. What is the pH's on the addition of the following strong base. a-) initially (Before adding NaOH) b-) Before the equivalence point (with the addition of 24.00 mL of 0.100 M NaOH) c-) At the equivalence point (with the addition of 25.00 mL of 0.100 M NAOH) d-) After the equivalence point(with the addition of 26.00 mL of 0.100 M NAOH) 0.025L nHt=0.0025nol HCISH4Cに *Al。t に

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

PROBLEMS
1)25.00 mL of 0.100 M HCl solution is titrated with a 0.1 M NAOH solution. What is the pH's on the addition
of the following strong base.
a-) initially (Before adding NaOH)
b-) Before the equivalence point (with the addition of 24.00 mL of 0.100 M NAOH)
c-) At the equivalence point (with the addition of 25.00 mL of 0.100 M NaOH)
d-) After the equivalence point(with the addition of 26.00 mL of 0.100 M NaOH)
0.025L
nHt=0.0025nol
a) -lop 0.1 = pHc
NaoH s Na f OH0.002

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