Problem Solving: 1. Two channels C12x25 are joined to 300 mm x W mm plates with 20 mm rivets to form a beam. The beam is simply supported having a span of 10 m. It is subjected to a maximum bending moment of Y kNm due to the uniformly distributed load (including beam self-weight) acting on entire span. (Hint: No NSCP involved, do not apply load factors

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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kindly please help me answer this question i have attached the reference to be use thanks

I
Problem Solving:
1. Two channels C12x25 are joined to 300 mm x W mm plates with 20 mm rivets to form a beam. The beam is
simply supported having a span of 10 m. It is subjected to a maximum bending moment of Y kNm due to the
uniformly distributed load (including beam self-weight) acting on entire span. (Hint: No NSCP involved, do
not apply load factors
a.
Calculate the moment of inertia in mm4.
b. Calculate the spacing of rivets (mm) if the shear capacity of a rivet is 10 kN.
Calculate the maximum bearing stress experienced by the rivets in kPa.
С.
Transcribed Image Text:I Problem Solving: 1. Two channels C12x25 are joined to 300 mm x W mm plates with 20 mm rivets to form a beam. The beam is simply supported having a span of 10 m. It is subjected to a maximum bending moment of Y kNm due to the uniformly distributed load (including beam self-weight) acting on entire span. (Hint: No NSCP involved, do not apply load factors a. Calculate the moment of inertia in mm4. b. Calculate the spacing of rivets (mm) if the shear capacity of a rivet is 10 kN. Calculate the maximum bearing stress experienced by the rivets in kPa. С.
W= 25 mm ,
W/2 = 12.5m
25 MPa
Y=155 KN , 155 KPa, 175 mm
W4 = 6.25m
Z=60
X+Z=535mm
X=475 KN
Transcribed Image Text:W= 25 mm , W/2 = 12.5m 25 MPa Y=155 KN , 155 KPa, 175 mm W4 = 6.25m Z=60 X+Z=535mm X=475 KN
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