Problem Number 2: In the givenflexible cable set-up carrying a uniformly distributed load spread horizontally has a magnitude of 5.5 KN/m. Fill-up the table belowfor the required data. Given the following materials specification, fy (cable) = 415 MPa, f.' (concr'te) = 24 MPa, Yconcrete = 23.5 KN/m³. Determine the Maximum Tension in The Cable = • Given the capacity of the cable, determine it's diameter =, • For the square post at B, what will be it's theoretical dimensions, x = KN. mm mm What will be the total Volume of the concrete at A to serve as dead man's load = m3 10 eters 25.00 meters 15.00 meters 20.00 meter L = 275.00 meters

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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help please need ASAP, thankssss 3rd decimal and FBD
Problem Number 2: In the given flexible cable set-up carrying a uniformly distributed load spread
horizontally has a magnitude of 5.5 KN/m. Fill-up the table belowfor the required data. Given the following
materials specification, fy (cable) = 415 MPa, f.' (concr'te) = 24 MPa, Yconcrete = 23.5 KN/m³.
Determine the Maximum Tension in The Cable =
KN.
Given the capacity of the cable, determineit's diameter=
For the square post at B, what will be it's theoretical dimensions, x =
mm
mm
What will be the total Volume of the concrete at A to serve as dead man's load =
m3
10 eters
25.00 meters
15.00 meters
20.00 meter
L= 275.00 meters
Transcribed Image Text:Problem Number 2: In the given flexible cable set-up carrying a uniformly distributed load spread horizontally has a magnitude of 5.5 KN/m. Fill-up the table belowfor the required data. Given the following materials specification, fy (cable) = 415 MPa, f.' (concr'te) = 24 MPa, Yconcrete = 23.5 KN/m³. Determine the Maximum Tension in The Cable = KN. Given the capacity of the cable, determineit's diameter= For the square post at B, what will be it's theoretical dimensions, x = mm mm What will be the total Volume of the concrete at A to serve as dead man's load = m3 10 eters 25.00 meters 15.00 meters 20.00 meter L= 275.00 meters
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