Problem n3 7.5 kg 14,=0.45 Knowing that 0= 40°, determine the smallest force P for which equilibrium of the 7.5-kg block is maintained.
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A: +↑ΣMA=0(Ey×8)−(10×4)−(8×6)=0Ey=11kN+↑⏐⏐∑Fy=0Ay+Ey=10−8=0⇒Ay=7kN
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A: Here, a figure is given. Also, it is given that, P = 165.8, Q = 249.3, R = 355.4, S = 268.2, T =…
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A: The free-body diagram of the system is shown below.
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Q: . Determine the force in each member of the truss
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