ProblemIn a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should be the expression for the horizontal distance dx at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance)SolutionTo determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation-h = vinitial-yt + (1/2)ay = _____If we just drop the package from the helicopter, the equation above becomes ___________ = ________ + (1/2)ay _______Substituting ay = -g then simplifying results tot = sqrt(_______ /_________ )which is the time it takes for the object to reach the ground.Since the package will just travel at a constant velocity in the x-axis, thusdx = vxtSubstituting the time taken by the package to reach to ground results to:dx = (_________)( sqrt (________/________ ) )which is the expression for the horizontal distance at which you should drop the package. ProblemIn a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What shouldbe the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at theright place? (Neglect the effect of air resistance)SolutionTo determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation-h = Vinitial-yt + (1/2)ayIf we just drop the package from the helicopter, the equation above becomes+ (1/2)aySubstituting ay = -g then simplifying results tot= sqrt(which is the time it takes for the object to reach the ground.Since the package will just travel at a constant velocity in the x-axis, thusdx = VxtSubstituting the time taken by the package to reach to ground results to:dx = (( sqrt ())which is the expression for the horizontal distance at which you should drop the package.

Given, initial velocity of helicopter is vx and horizontal distance is dx

Answered: Problem In a relief operation mission…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem

In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity v_x. What should be the expression for the horizontal distance d_x at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance)

Solution

To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation

-h = v_initial-yt + (1/2)a_{y = _____}

If we just drop the package from the helicopter, the equation above becomes

___________ = ________ + (1/2)a_{y _______}

Substituting a_y = -g then simplifying results to

t = sqrt(_______ /_________ )

which is the time it takes for the object to reach the ground.

Since the package will just travel at a constant velocity in the x-axis, thus

d_x = v_xt

Substituting the time taken by the package to reach to ground results to:

d_x = (_________)( sqrt (________/________ ) )

which is the expression for the horizontal distance at which you should drop the package.

Problem
In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should
be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the
right place? (Neglect the effect of air resistance)
Solution
To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation
-h = Vinitial-yt + (1/2)ay
If we just drop the package from the helicopter, the equation above becomes
+ (1/2)ay
Substituting ay = -g then simplifying results to
t= sqrt(
which is the time it takes for the object to reach the ground.
Since the package will just travel at a constant velocity in the x-axis, thus
dx = Vxt
Substituting the time taken by the package to reach to ground results to:
dx = (
( sqrt (
))
which is the expression for the horizontal distance at which you should drop the package.

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