In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should be the expression for the horizontal distance dx at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = vinitial-yt + (1/2)ay_____ If we just drop the package from the helicopter, the equation above becomes _____= _____ + (1/2)ay_____ Substituting ay = -g then simplifying results to t = sqrt( _____/_____ ) which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = vxt Substituting the time taken by the package to reach to ground results to: dx = ( _____ )( sqrt ( / ) ) which is the expression for the horizontal distance at which you should drop the package.
Problem
In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should be the expression for the horizontal distance dx at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance)
Solution
To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation
-h = vinitial-yt + (1/2)ay_____
If we just drop the package from the helicopter, the equation above becomes
_____= _____ + (1/2)ay_____
Substituting ay = -g then simplifying results to
t = sqrt( _____/_____ )
which is the time it takes for the object to reach the ground.
Since the package will just travel at a constant velocity in the x-axis, thus
dx = vxt
Substituting the time taken by the package to reach to ground results to:
dx = ( _____ )( sqrt ( / ) )
which is the expression for the horizontal distance at which you should drop the package.
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