VERSIPROBLEM: Consider the cross section shown. All structural steel is A992. Use LRFD and ASDmethod and NSCP(AISC) specifications. For A992 steel; Fy = 345 MPa; Fu = 448 MPa1. Determine the governing effective length2. Determine the minor and major axisDETERMINE THE FOLLOWING:3. Determine the governing slenderness ratio.4. Determine the design capacity of the column using ASD method. -2-C8x18.75C8x 18.75= 3,555 mm?bf = 64.2 mMtf = 9.9 mmtw = 12.4 mmd = 203.2 mm* = 14.35 mmIx = 18.31 x 10 mm= 0.82 x10° mmMINOR AXISMA JOR AXISCONDITIONS OF LATERAL BRACINGSAND END SUPPORTSly:0006000S0007

Answered: Image /qna-images/answer/702b8653-b1b6-4bdc-9d99-35a1589b38ce.jpg

PROBLEM: Consider the cross section shown. All structural steel is A992. Use LRFD and ASD method and NSCP(AISC) specifications. For A992 steel; Fy = 345 MPa; Fu = 448 MPa DETERMINE THE FOLLOWING: 1. Determine the governing effective length 2. Determine the minor and major axis 3. Determine the governing slenderness ratio. 4. Determine the design capacity of the column using ASD method. VERSI

PROBLEM: Consider the cross section shown. All structural steel is A992. Use LRFD and ASD method and NSCP(AISC) specifications. For A992 steel; Fy = 345 MPa; Fu = 448 MPa DETERMINE THE FOLLOWING: 1. Determine the governing effective length 2. Determine the minor and major axis 3. Determine the governing slenderness ratio. 4. Determine the design capacity of the column using ASD method. VERSI

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

PROBLEM 2. The lap joint in the figure is made using a 30 mm diameter bolt. The outer plates are 5 mm thick, made of 2014- T6 aluminum and the inner plate is 10 mm thick and made of 6061-T6 aluminum. The bolt is made of S355 steel material. Calculate the load P that the lap joint can safely support, taking into account the failure of the plates by shear and tension and failure of the bolt by bearing and shear. Use a factor of safety for ultimate strength of F.S.=1.5 100 min 20 m P/2 P/2
A composite bar BCD has a uniform external radius R. = 9cm. Segment BC is solid steel, while segment CD is composed of a copper core of radius R.= 1cm bonded inside a steel sleeve. The lengths of the two segments are LBc= 2 m and LCD= 1 m. The material moduli are Esel= 200 GPa and Ecoppe,= 100 GPa. The bar is fixed at B and tensile loads are applied at section D (F»= 1000 kN) and at section C (Fc=400 kN). Compute the following: Determine the axial stress of copper in segment CD in MPa. 2m B 1m D 400 KN 1000 KN
determine: (a) the elastic section modulus and the yield moment. (b) the plastic section modulus and the plastic moment Mp. Bending is about the x-axis, and the steel is A572 Grade 50. Fy = 345 MPa Subject: Civil Engineering Steel Design
A steel plate (called a cover plate) having cross-sectional dimensions W2 8.0 in. x 0.7 in. is welded along the full length of the bottom flange of a W, 12.0 in. x 14.0 in. wide-flange beam (see the figure, which shows the beam cross section). I W2 cover plate What is the percent increase in the smaller section modulus (as compared to the wide-flange beam alone)? Round your answer to two decimal places. % in smaller section modulus =|
AW18 x 40 standard steel shape is used to support the loads shown on the beam. Assume P = 20 kips, w = 4.8 kips/ft, LAB = 4.2 ft, Lec = 4.2 ft, and Lco = 16.0 ft. Determine the magnitude of the maximum bending stress in the beam. P B C D LAB LBC LCD Answer: Omax = i ksi
Problem2. The compression member is shown in figure. Find the following: a. The Euler stress Fe. b. The buckling stress Fcr c. The design strength d. The allowable strength e. Does the member satisfactorily meet the design requirements? Why? HSS 8x 8x4 ASTM AS00, Grade B steel (Fy = 46 ksi) 15'
A composite bar BCD has a uniform external radius R. = 9cm. Segment BC is solid steel, while segment CD is composed of a copper core of radius R:= 1cm bonded inside a steel sleeve. The lengths of the two segments are LBc= 2 m and LcD= 1 m. The material moduli are Etei= 200 GPa and Ecope= 100 GPa. The bar is fixed at B and tensile loads are applied at section D (F»= 1000 kN) and at section C (Fc=400 kN). Compute the following: Determine the axial stress of steel in segment CD in MPa. 2m B 1m D 400 KN 1000 KN
Assume A992 steel in all your calculations. an existing I‐shaped crosssection is reinforced with a C‐Channel shape as shown in the figure below. What is the elastic neutral axis depth ( yna ) and the plastic neutral axis depth ( ypna )
A 6.1 m long steel column is fixed at its base and pinned at the top end. The cross section is a W360×57. The steel has a yield strength oy = 250 MPa. a) Determine the critical load, Per b) What is the maximum column length to ensure failure due to yielding instead of buckling?
Given the truss shown, solve the following. Use A36 steel and assume there are two lines of three 19 mm bolts in each flange. Hole diameter is assumed to be three mm more than the bolt diameter. Neglect the weight of the section. a.What is the capacity of member CG? b. Design member CG using a W section. c. What is the tensile capacity of the section for CG based on gross area? The following W Section were considered for the design: W10x33 W14x38 W8x40 W16x36 W10x39 W8x13 189 KN 1.50 HL B 145 KN 1.50 E + 137 KN 121 KN -3.00 + 12.00 3.00 154 KN + W4x13 W6x9 W10x12 200 KN -1.50 1.50 1 030 T 1.20 +2.40 0.60 L i 0.30
A composite bar BCD has a uniform extemal radius R, = (x+2) cm. Segment BC is solid steel, while segment CD is composed of a copper core of radius R;= 1cm bonded inside a steel sleeve. The lengths of the two segments are Lgc = 2 m and LCD= 1 m. The material moduli are Esel = 200 GPa and Ecoper = 100 GPa. The bar is fixed at B and tensile loads are applied at section D (FD = 1000 kN) and at section C (Fc = 400 kN). Compute the following: 1. Axial stress of steel in segment BC in MPa. 2. Axial stress of steel in segment CD in MPa. 3. Axial stress of copper in segment CD in MPa. 4. Total elongation of the assembly in mm. 2m в 1m 400 KN 1000 KN
Determine the design strength and the allowable strength for the compression member shown. Use NSCP 2015 and a steel with Fy =50ksi. L3X2.5X1/4 kL = 8ft PL 3/8 X 8 L3X2.5X1/4