Solutiona)Let us first derive the expression for the tension.By Newton's First LawEF =the components of force that makes this so isEF = T= 0Simplifying this results toT =g/(4)Analyzing the figure above, we arrive at(4) = sqrtt2+By substitution, we arrive at the following:T=+ 2sqrt (2+))If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal toT =0.370 N+ ProblemA solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension inthe wire.Lm

The mass of the solid uniform ball, m=45 kg The diameter supported against the frictionless wall,…

Answered: Problem A solid uniform ball with mass…

Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

Solution
a)
Let us first derive the expression for the tension.
By Newton's First Law
EF =
the components of force that makes this so is
EF = T
= 0
Simplifying this results to
T =
g/
(4)
Analyzing the figure above, we arrive at
(4) = sqrtt
2+
By substitution, we arrive at the following:
T=
+ 2
sqrt (
2+
))
If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to
T =
0.370 N
+

Problem
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in
the wire.
L
m

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