### Physics Example Problem: Tension in a Cable Supporting a Horizontal Bar#### Problem DescriptionConsider a horizontal bar of length \( L = 1.3 \) meters and mass \( m_b = 15 \) kg that is hinged at one end (left end). This bar is held in place by a cable attached at the other end (right end). The cable makes an angle of \( 29^\circ \) with the horizontal. Suspended below the bar at a distance \( d = 0.18 \) meters from the right end is a store sign with a mass \( m_s = 18 \) kg.#### ObjectiveDetermine the magnitude of tension in the cable that supports the bar and the suspended store sign.#### Diagram ExplanationThe diagram represents the setup described:- A vertical wall on the left supports the hinged end of the bar.- A horizontal uniform bar is shown, with \( L \) labeled along its length.- The bar’s mass (\( m_b \)) is centered along its length.- A cable runs from the right end of the bar to the wall, creating an angle \( \theta = 29^\circ \) with the horizontal.- A store sign with mass \( m_s \) is suspended 0.18 meters from the right end of the bar.#### Given Data- Length of the bar, \( L = 1.3 \) meters- Mass of the bar, \( m_b = 15 \) kg- Angle between the cable and horizontal, \( \theta = 29^\circ \)- Mass of the store sign, \( m_s = 18 \) kg- Distance from the right end of the bar to the store sign, \( d = 0.18 \) meters#### Solution Approach1. Compute the torques acting on the bar around the hinge.2. Use static equilibrium conditions (sum of forces and sum of torques being zero) to find the tension in the cable.**Step-by-Step Calculation:**1. **Calculations** - Calculate the gravitational force on the bar: \[ F_b = m_b \cdot g = 15 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 147 \, \text{N} \] - Calculate the gravitational force on the store sign: \[

Answered: Image /qna-images/answer/b289536e-c7d1-4a42-8cac-b00c74e1e729.jpg

A horizontal L=1.3 m long mb=15 kg uniform bar is hinged on the left end and pulled at the right end by a cable. The cable makes 29° angle with horizontal. A 18 kg store sign is suspended below the bar at d=0.18 m from the right end.

A horizontal L=1.3 m long mb=15 kg uniform bar is hinged on the left end and pulled at the right end by a cable. The cable makes 29° angle with horizontal. A 18 kg store sign is suspended below the bar at d=0.18 m from the right end.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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