Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1?

Solution

To solve for the work done, first we must determine what is the final kinetic energy of the electron.

Problem
A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter
as fast in the opposite direction. What is the work done W in terms of Kg?
Solution
To solve for the work done, first we must determine what is the final kinetic energy of the electron.
By concept, we know that
K-(1/2)mv2,
K2=(1/2)mv2
But it was mentioned that:
V2-
so, K2 in terms of v, is
K2=(
)mv2,
Substituting the expression for K, results to
K2=(
)K1
Since work done is
W-AK=K
-K
Evaluating results to
W=(
)K1
Transcribed Image Text:Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of Kg? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K-(1/2)mv2, K2=(1/2)mv2 But it was mentioned that: V2- so, K2 in terms of v, is K2=( )mv2, Substituting the expression for K, results to K2=( )K1 Since work done is W-AK=K -K Evaluating results to W=( )K1
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