Problem 9. Which of the following each answer. NOTE: For this problem, I do not r rigorous definition of continuity. You of continuity given at the beginning o continuity at the end of the lecture. answer questions about continuity mor a. f: R→R, f(x) = ecos, b. f:I→R, f(x) = ecos, c. f: R→ R²2, f(x) = (e, sin x), d. f: R→ R², f(x) = [(x,z (x₂ A 3
Problem 9. Which of the following each answer. NOTE: For this problem, I do not r rigorous definition of continuity. You of continuity given at the beginning o continuity at the end of the lecture. answer questions about continuity mor a. f: R→R, f(x) = ecos, b. f:I→R, f(x) = ecos, c. f: R→ R²2, f(x) = (e, sin x), d. f: R→ R², f(x) = [(x,z (x₂ A 3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Transcribed Image Text:Problem 9. Which of the following functions are continuous? Briefly justify
each answer.
NOTE: For this problem, I do not necessarily expect you to appeal to the
rigorous definition of continuity. You may appeal to the intuitive descriptions
of continuity given at the beginning of the lecture, as well as the facts about
continuity at the end of the lecture. (In the future, you may be expected to
answer questions about continuity more rigorously, but not here.)
a. f: R→R, f(x) = ecos,
b. f:I→R, f(x) = ecos,
c. f: R→ R², f(x) = (eª, sin x),
d. f: R→ R²,
f(x) =
[(x,x+3) if x ≥ 0,
(x,-x) if x < 0,
A
3
![e. f: R→ R²,
f(x) =
.f
=
[(x,x) if x # 0,
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noinut od 11 moitoojid 10 moitosure moitoojui as ei noitonut od) routed ye
Stovai esi ovia els noitootid & i
²x = (1)1 <-:1.8
one of nofiston taid od on tar) (3) = (x)\.:\d
x = (x) Я +Я:
=(s)1.(∞0,0] : 1 b
x 800 = (s)[1.1-) - :\ 9
x) = (s) + #:\4
bus 2 and bootersbau ei si 91H) x = (.)
+ 1x¹2:0
(1
(x) = (.) 2:
.8 moldorT
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(1.0) (1,0): oinojid s svi [bobag od ton liw, 10 d
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lt of loys of og heimsson jon ob I moldong aldt 101 TO
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Transcribed Image Text:e. f: R→ R²,
f(x) =
.f
=
[(x,x) if x # 0,
bas ogami ali tol notezon vioileze as evignoitant dos 101 T maldorl
noinut od 11 moitoojid 10 moitosure moitoojui as ei noitonut od) routed ye
Stovai esi ovia els noitootid & i
²x = (1)1 <-:1.8
one of nofiston taid od on tar) (3) = (x)\.:\d
x = (x) Я +Я:
=(s)1.(∞0,0] : 1 b
x 800 = (s)[1.1-) - :\ 9
x) = (s) + #:\4
bus 2 and bootersbau ei si 91H) x = (.)
+ 1x¹2:0
(1
(x) = (.) 2:
.8 moldorT
$1 to visit at 1sdW (00, 1] + [1,0): 1 moitosjid & svi s
(1.0) (1,0): oinojid s svi [bobag od ton liw, 10 d
vitani vitsind faroutboos ons auoitoul guvollot sdt lo doidW.0 moldor T
lt of loys of og heimsson jon ob I moldong aldt 101 TO
alignesh svitbytai ods of Isoqqs ve BOY viimituoo to moitiaftob ancian
tuoda abel and so flow an outsol si to guimigod od 1
of botoqxs ed your owul entaill
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