Problem (8)The rigid bar ABC in the figure is Figure P-268pinned at B and attached to the twovertical rods. Initially, the bar isSteelL = 0.9 mA 300 mm2E = 200 x 10 N/m2a 11.7 um/(m-°C)AluminumL = 1.2 mA = 1200 mm²E = 70 x 10 N/m2α- 23 μη/ (m."C)horizontal and the vertical rods arestress-free. Determine the stress in thealuminum rod if the temperature of thesteel rod is decreased by 40°C.Neglect the weight of bar ABC.Solution:0.6 m1.2 m

Given data as per questionfor steelL=0.9 mA=300mm2E=200×109 Nm2α=11.7μm/(m0c)Distance between AB=0.6…

Problem (8) The rigid bar ABC in the figure is Figure P-268 pinned at B and attached to the two vertical rods. Initially, the bar is horizontal and the vertical rods are Aluminum Steel L = 0.9 m A 300 mm? E = 200 x 10° N/m2 a = 11.7 um/(m-°C) L = 1.2 m A = 1200 mm2 E = 70 x 10° N/m2 a = 23 um/(m-°C) stress-free. Determine the stress in the aluminum rod if the temperature of the steel rod is decreased by 40°C. Neglect the weight of bar ABC. C Solution: 0.6 m 1.2 m

Problem (8) The rigid bar ABC in the figure is Figure P-268 pinned at B and attached to the two vertical rods. Initially, the bar is horizontal and the vertical rods are Aluminum Steel L = 0.9 m A 300 mm? E = 200 x 10° N/m2 a = 11.7 um/(m-°C) L = 1.2 m A = 1200 mm2 E = 70 x 10° N/m2 a = 23 um/(m-°C) stress-free. Determine the stress in the aluminum rod if the temperature of the steel rod is decreased by 40°C. Neglect the weight of bar ABC. C Solution: 0.6 m 1.2 m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Find the Tensions TCA and TCB for the system as shown in figure. Take R = 200 mm, S= 240 mm 0 = 55°, W= 14 kN ( Solve the problem in a paper and upload the file in a separate link provided. Also enter only the values in the boxes below. ) Tension TCA in N is Tension TCB in N is
i need the answer quickly
Problem 4 A weight W = 75 kN is applied eccentrically from the end of a cantilevered circular pipe of length L 750 mm, as shown in the figure below. Points A and B lie in the vertical and horizontal axes, respectively, on a cross section located at a distance L₁ = 350 mm from the end. The outer diameter is do = 200 mm, the wall thickness is t = 5 mm, and a fluid in the pipe introduces a pressure p = 10 MPa. 1. Calculate the absolute maximum normal and shear stresses at point A. 2. Calculate the absolute maximum normal and shear stresses at point B. L Figure 4: Problem 4.
Gkuestrons T ØD VP The figure (not drawn to scale) shows a metallic cylindrical column submitted to a combined load: bending and torsion. The column contains an hemispherical groove of radius r, located at a distance L from the point of application of the loads. You are given the column diameter D = 68 mm, the groove radius r = 6 mm, the distance L= 200 mm, the bending load P=5 kN, and the torque T = 600 N.m. The material data are Young's modulus E = 122 GPa Shear Modulus G = 55 GPa Poisson's ratio v= 0.1 and Yield strength oy = 380 MPa. a) Write a numbered list of the calculation steps required to obtain the factor of safety in yielding based on the maximum distortion energy (Von Mises) criterion.
5
A solid steel bar of diameter di = 1.4 in. is enclosed by a steel tube of outer diameter d3 = 2.25 in. and inner diameter d2 = 1.9 in. (see the figure). Both bar and tube are held rigidly by a support at end A and joined securely to a rigid plate at end B. The composite bar, which has length L = 26 in., is twisted by a torque T = 5,100 lb-in. acting on the end plate. Tube A Bar End plate (a) Determine the maximum shear stresses T1 and T2 in the bar and tube, respectively. Round your answers to the nearest whole number. T1 = psi T2 = psi (b) Determine the angle of rotation (in degrees) of the end plate, assuming that the shear modulus of the steel is G = 11.5 × 10° psi. Round your answer to three decimal places. (c) Determine the torsional stiffness kT of the composite bar. Round your answer to the nearest whole. [Hint: Use equations below to find the torques in the bar and tube.] T = T GIp, + G2IP, kT = k-in.
Rijit 1,2 m 0,6 m- 1 m Çap:50 mm The system in the figure is carried by a 50 mm diameter column. If the modulus of elasticity of the column is 70 GPa, find the maximum load q that the column can carry.
2-) Consider the thin (steel) plate in figure given below. The plate has a uniform thickness t= 1 cm., Young's modulus E = 25 x 10° N/cm?, and weight density p= 0,2448 N/cm³. In addition to its self-weight, the plate is subjected to a point load P = 200 N at its midpoint. (Please be careful for the units.) (a) Model the plate with two finite element. 12 cm (b) Write down expressions for the element stiffness matrices and 18 cm element body force vectors. (c) Assemble the structural stiffness matrix K and global load 36 cm vector F.(' P =200N (d) Using the elimination approach, solve for the global displacement vector Q. (e) Evaluate the stresses in each element. ( -. X 6 ст
Axial loads are applied with rigid bearing plates to the solid cylindrical rods shown in the figure. One load of P=33P=33 kipskips is applied to the assembly at A, two loads of Q=30Q=30 kipskips are applied at B, and two loads of R=35R=35 kipskips are applied at C. The normal stress magnitude in aluminum rod (1) must be limited to 1717 ksiksi. The normal stress magnitude in steel rod (2) must be limited to 3030 ksiksi. The normal stress magnitude in brass rod (3) must be limited to 2121 ksiksi. Determine the minimum diameter required for each of the three rods.
The figure below shows a section of a column subjected to load P, which is applied 50 mm from the midline of the section's web. The column is made from material, which has an allowable normal stress of 180 MPa (both in tension and compression). The area of the section is 10050 mm?; the principal moments of inertia Imar = 146.554x106 mm and Imin 20.076x10° mm*. !! Determine the maximum allowable load P. 15 mm 150 mm 15 mm 150 mm 50 mm 15 mm 100 mm 100 mm 1194.6 kN 363.6 kN 1809.0 kN O 516.4 kN O 189.5 kN
A steel ring at a room temperature has a radius of R, of 1.00 mm x 1.00 mm. One like to insert a bar of radius R, = 2.002 cm into the ring. The following data is known for steel: 2.00 cm and a cross section area • Young Modulus E = 2.00 × 1011 Pa. • Coefficient of length contraction a = 1.20 x 10-5 C-1 • Specific heat capacity c = 511 J.kg-1.C-1 • Mass density p= 8050 kg.m -3 (a) What is the amount of heat needed for heating the ring so that the rod can fitted into it. (b) Assume the rod is rigid, calculate the pressure on the surface of the rod as the steel cool down to the room temperature.
None