Problem:75 mm diam. shaft12,000 N16,000 N900 mm900 mm900 mm900 mm4,000 NRR,300 mm20,000 NFor the loading shown, find thea) Find the value of the reaction R,A. R, = 6,000 N ↑B. R, = 6,400 N 4C. R1 = 6,000NID. R, = 6,400 N 1None of theseb) Find the value of the reaction R2C. R2 = 2,300 N ↑D. R2 = 2,400NIA. R, = 2,300 NIE. None of theseB. R2 = 2,400N↑c) shear force at a point 1,950 m from the left end of the beam.A. V = 16,000 NB. V = 14,400 NC.12,000 N D. 5,600 NPage 1 of 2d) Find the value of the maximum Bending stress for the system of loading asin Figure below at a section on a point on the shaft 1, 950 mm from the leftend of the beam. Neglect the weight of the beam.A. o, = +99.54 MPaB. o, = + 89.54 MPaC. O =+79.54 MPaD. o, = + 69.54 MPae) Find the value of the maximum Transverse shear stress for the system ofloading as in Figure at a section on a point located 1, 950 mm from the leftend of the beam. Neglect the weight of the beamA. (T)max = 6.35 MPaB. (Ter)max = 5.35 MPaC. (Tr)max = 4.35 MPaD. (Ttr) max = 3.35 MPa

As per our guidelines we are supposed to solve only 3 subparts if multiple subparts are asked .…

Problem: 75 mm diam. shaft 12,000 N 16,000 N 900 mm 900 mm 900 mm 900 mm 4,000 N R, 300 mm 20,000 N For the loading shown, find the a) Find the value of the reaction R, A. R, = 6,000 N ↑ B. R, = 6,400 N 4 C. R = 6,000 N ! D. R = 6,400 N 1 E. None of these %3D %3D b) Find the value of the reaction R2 C. R2 = 2,300 N ↑ E. None of these D. R2 = 2,400 N! A. R2 = 2,300 N ! B. R2 = 2,400 Nt c) shear force at a point 1,950 m from the left end of the beam. A. V = 16,000 N C. 12,000 N D. 5,600 N B. V = 14,400 N

Problem: 75 mm diam. shaft 12,000 N 16,000 N 900 mm 900 mm 900 mm 900 mm 4,000 N R, 300 mm 20,000 N For the loading shown, find the a) Find the value of the reaction R, A. R, = 6,000 N ↑ B. R, = 6,400 N 4 C. R = 6,000 N ! D. R = 6,400 N 1 E. None of these %3D %3D b) Find the value of the reaction R2 C. R2 = 2,300 N ↑ E. None of these D. R2 = 2,400 N! A. R2 = 2,300 N ! B. R2 = 2,400 Nt c) shear force at a point 1,950 m from the left end of the beam. A. V = 16,000 N C. 12,000 N D. 5,600 N B. V = 14,400 N

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Instruction: Present the solution as instructed and draw the free body diagram. PS N0. 1. Determine the reaction forces in the following structures:
Solve all reactions of pin reactions
3) Supported and truss like in the figure; a) Calculate the support reactions a) Find the rod forces relative to the knot point
5:37 PM 53% ubian.ub.edu.ph/student 10 2 14 University of Batangas Question 5 of 6 2 Points Fill in the blanks: Q3. Determine the inner and outer diameter of the hollow shaft which will replace a 76 mm solid shaft made of the same material. The hollow shaft should be as strong in torsion but it weighs only half as much as the solid. ANS: Do = || mm, Dj = mm (Whole Number) ( Previous Continue > II
a) P1=13 kN and P2= 6.5 kN. Compute reaction at B. b)P1=13 kN and P2= 6.5 kN. W= 27.5 kN is applied at D. Compute reaction at B and compute for member CD c)
Needs Complete typed solution with 100 % accuracy. Handwritten solution is completely prohibited.
following: 6m A Given the three - hinged arch as shown below. Determine the a.) The Vertical Component of Reaction at Point A. b.) The Vertical Component of Reaction at Point B. c.) The Horizontal Component of Reaction at Point B. 700 N C 45° 6 panels @2.0 m = 12.0 m 600 N Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. 500 N 6 m B
In the position shown in figure shown, the block of mass 100 kg just contacts the free end of the spring with constant k-6000N/m (a) If the block is released instantaneously with zero initial velocity, find the m lection of the spring (b) Find the max deflection, if the block is very gradually lowered onto spring. 100kg Free end ANS: a.)|| m b.) m (two decimal places)
a) A steel 4 X 4X 0.25-inch square tube (moment of inertia I = 8.215 inª) is used as a simply supported beam. A 100-pound weight is dropped from a height of 24 inches onto the beam at mid- span. Find the maximum stress in the beam. Use E = 29 X 106 psi. 8 ft k = 200 lb/in 100 lb 8 ft b) Instead of fixed supports, the beam is supported by springs at both ends. Find the maximum stress in the beam when the 100-pound weight is dropped from a height of 24 inches (same beam properties as in part a). 24 in 100 lb 8 ft 24 in 8 ft k = 200 lb/in
2 b) METHODS OF SECTIONS
Q3: Draw the S.F and B. M. diagrams for the beam shown below. P = 625 lb L%3D4 ft 9=80 lb/ft %3D L2 = 8 ft L3 = 5 ft
Q2/ Use the unit load method to find the slope and the horizontal displacement of point C on the frame shown below. E=200 GPa, I=200 x 10 mm 5 m B C 4 kN El 2 kN/m 6 m 1.5 EI A. For real load, horizontal reaction Ax= * Your answer For real load, vertical reaction Ay= * Your answer For real load, vertical reaction Cy= * Your answer For Unit load (horizontal displacement), horizontal reaction Ax= * Your answer For Unit load (horizontal displacement), vertical reaction Ay= * Your answer For Unit load (horizontal displacement), vertical reaction Cy= * Your answer