Problem 7: The load that will be applied to the connection shown has a live load - to - dead loadratio of 3.0. Investigate all limit states. All structural steel is A36, and the weld is a 1/4-inch filletweld with E70 electrodes. Note that the tension member is a double-angle shape, and both of theangles are welded as shown. Use ASD. Determine the following.5"5"2L5 X 32 X 5/16 LLBB-t = ³/8"Maximum service load that can be applied withoutexceeding the allowable capacity on yielding ongross area of the tension member (double angle).Maximum service load that can be applied withoutexceeding the allowable fracture on the net areaof the tension member (double angle).Maximum service load that can be applied withoutexceeding the allowable block shear strength.Considering the weld metal and base metalstrength, calculate the maximum service load thatcan be applied.

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Problem 7: The load that will be applied to the connection shown has a live load - to - dead load ratio of 3.0. Investigate all limit states. All structural steel is A36, and the weld is a 1/4-inch fillet weld with E70 electrodes. Note that the tension member is a double-angle shape, and both of the angles are welded as shown. Use ASD. Determine the following. 5" 5" 2L5 X 3¹/2 X 5/16 LLBB

Problem 7: The load that will be applied to the connection shown has a live load - to - dead load ratio of 3.0. Investigate all limit states. All structural steel is A36, and the weld is a 1/4-inch fillet weld with E70 electrodes. Note that the tension member is a double-angle shape, and both of the angles are welded as shown. Use ASD. Determine the following. 5" 5" 2L5 X 3¹/2 X 5/16 LLBB

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Problem 7: The load that will be applied to the connection shown has a live load - to - dead load
ratio of 3.0. Investigate all limit states. All structural steel is A36, and the weld is a 1/4-inch fillet
weld with E70 electrodes. Note that the tension member is a double-angle shape, and both of the
angles are welded as shown. Use ASD. Determine the following.
5"
5"
2L5 X 32 X 5/16 LLBB
-t = ³/8"
Maximum service load that can be applied without
exceeding the allowable capacity on yielding on
gross area of the tension member (double angle).
Maximum service load that can be applied without
exceeding the allowable fracture on the net area
of the tension member (double angle).
Maximum service load that can be applied without
exceeding the allowable block shear strength.
Considering the weld metal and base metal
strength, calculate the maximum service load that
can be applied.

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Step 2: a) Calculation of maximum service load on yielding on gross area

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Step 3: b. Calculation of maximum service load on net area:

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Step 4: c. Calculation of maximum service load on block shear strength

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