M Trans TransWelc E UGALMApplyA ApplyFuturG bestW AcadG mostG electO (3) EW Beco wW Regis M InboC Xum.ecollege.com/course.html?courseld=16544025&OpenVellumHMAC%=Daf9c488c61261c3da6bdc65b0005e9a9#10001UpcGmail 9 Maps Web design tutori. W MATH180: HW08-..Winter 2021 PHYS 231 03Hi, ala vSign Out"sicsCourse HomeSCH6HWProblem 6.32 - Enhanced - with Hints and Feedback3 of 8I Review I ConstantsYou and your friend Peter are putting new shingleson a roof pitched at 24°. You're sitting on the verytop of the roof when Peter, who is on the edge cthe roof, 5.5 m away, asks you for the box of nails.Rather than carry the 2.5 kg box of nails down toPeter, you decide to give the box a push and haveit slide down to him.a ofPart AIf the coefficient of kinetic friction between the box and the roof is 0.55, with what speed should you push the box to have itgently come to rest right at the edge of the roof?Express your answer to two significant figures and include the appropriate units.> View Available Hint(s)THHẢ?v = 4,4SubmitPrevious AnswersX Incorrect; Try Again; 2 attempts remainingProvide FeedbackNext >steringphysics.com/myct/itemView?assignmentProblemiD=150494463MacBook Pro20000D00DIIDDF4F5F6F7FBF9F10F11F12F1F2F3&*23$%14.8delete{QWEYUSFGH.JKretuCVMoptioncommandcommandoption.. ..B

Solution: From the above-given data, We have, N=mgcosθ (when no motion perpendicular to…

Answered: Problem 6.32 - Enhanced - with Hints…

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Move over Jeff Bezos, this invention is about to make you the richest person in the world. You have just invented the OyOy (that's YoYo spelled backwards). It is the very latest in home safety and so easy to use!If your building is on fire, simply reach out and grab the cord on the OyOy and you will be lowered safely toward the ground at a low velocity. The OyOy has a total mass M = 94.0 kg and is shaped like a cylinder of radius R = 0.810 meters. The secret to the operation of the OyOy is its patented shaft whose radius is only r = 0.0800 meters. The cord is wound around the small shaft and this is the secret to your low velocity. We will use the approximation that the shaft is of negligible mass compared to the total. This means that you can treat the entire OyOy as though it is a solid cylinder with mass M and radius R. Imagine that a customer of mass m = 85.5 kg is using the OyOy and begins his decent from an initial height of y0 = 11.20 meters.Determine all the following:The…
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A spring-loaded ball launcher (I)Context A spring-loaded ball launcher is embedded in the floor. When the ball launcher is triggered, the ball is propelled into the air and then falls to the ground. We are looking for the horizontal distance travelled by the ball. Information The pitcher is tilted at a known angle theta.The spring, whose spring constant is known, is initially compressed.At its natural length, the end of the spring coincides with the ground.The mass of the ball is known, but its diameter is neglected. Modelization Create a model (a single equation!) for the horizontal distance the ball travels (in metres) from the mouth of the pitcher to where it hits the ground. Then test your model with the following values: Pitch launcher lean angle(theta): 22.2 degrees Spring constant: 64.1 N/m Initial spring compression: 19.8 cm Ball mass A : 130 g
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A spring-loaded ball launcher (I)Context A spring-loaded ball launcher is embedded in the floor. When the ball launcher is triggered, the ball is propelled into the air and then falls to the ground. We are looking for the horizontal distance travelled by the ball. Information The pitcher is tilted at a known angle theta.The spring, whose spring constant is known, is initially compressed.At its natural length, the end of the spring coincides with the ground.The mass of the ball is known, but its diameter is neglected. Find the horizontal distance the ball travels (in metres) from the mouth of the pitcher to where it hits the ground with these following values: Pitch launcher lean angle(theta): 22.2 degrees Spring constant: 64.1 N/m Initial spring compression: 19.8 cm Ball mass A : 130 g
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QUESTION 1 Three boxes are placed on a seesaw. Box #1 (8 kg) is placed at the very end of the left side of the 3.4 m long seesaw. Box #2 (13 kg) is placed at the other end of the seesaw. The pivot point of the seesaw is 0.2 m to the left of the middle of the seesaw. + How far away from the pivot point would you need to place Box #3 (31 kg) for the seesaw to be balanced? A. 0.4 + Would you need to place Box #3 to the left or right of the pivot for the seesaw to be balanced? В. -124 + What is the net torque if Box #3 were placed at the pivot point? C. Left D. 4.3 Е. 8.5 F. Right G. 1 Н. 1.3 I. -8.5 J. 0.6 K. 124 L. -4.3 M. 0.3
6:23 PM Tue Dec 7 a 11% Signature E MasteringPhysi X Content New Tab Question 1 of 3 X Question 16 of X MasteringPhysi X Q Chapter 3 Flash X + A session.masteringphysics.com 53 KExtra credit assignment - Attempt 1 Problem 7.55 18 of 20 Constants Part A Suppose you were to drop a 16 lb bowling ball from the top of the Empire State Building, which is about 440 m tall, onto a machine that would catch it and then convert its kinetic energy into electrical energy. For how long could the resulting energy light a 110 W light bulb? Express your answer in seconds. ? t = S Submit Request Answer Part B Is it actually possible to convert mechanical energy to electrical energy with 100% efficiency? Yes No Submit Request Answer Provide Feedback Next >

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