Problem 6. Fox Fork Fabrication Fox Factory Inc. is testing a new fork design. A step force of F= 2kN is applied to the fork and its vertical response y(t) is recorded. The fork is modeled as a spring-mass-damper system as depicted in the figure. The mass m is given by m = 2 kg. The final value of the system is found to be 200 millimeters or 0.2 m. The temporal positions of the peaks indicated in the figure are t₁ = 0.0725 s and t₂ = 0.2177 s. Find the values of k and b. m k b F у y(t) F.V. t₁ t₂ t

Problem 6. Fox Fork Fabrication Fox Factory Inc. is testing a new fork design. A step force of F= 2kN is applied to the fork and its vertical response y(t) is recorded. The fork is modeled as a spring-mass-damper system as depicted in the figure. The mass m is given by m = 2 kg. The final value of the system is found to be 200 millimeters or 0.2 m. The temporal positions of the peaks indicated in the figure are t₁ = 0.0725 s and t₂ = 0.2177 s. Find the values of k and b. m k b F у y(t) F.V. t₁ t₂ t

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Free undamped vibrations

Whenever an object/system displaces in either side of its equilibrium position with the help of an external/internal means, then the object/system moves regularly or randomly on both sides of its equilibrium position. This motion is called vibration. Generally, there are three types of vibration: longitudinal vibration, transverse vibration, and torsional vibration.

Question

Problem 6. Fox Fork Fabrication
=
Fox Factory Inc. is testing a new fork design. A step force of F 2kN is applied to the
fork and its vertical response y(t) is recorded. The fork is modeled as a spring-mass-damper
system as depicted in the figure. The mass m is given by m = 2 kg. The final value of
the system is found to be 200 millimeters or 0.2 m. The temporal positions of the peaks
indicated in the figure are t₁ = 0.0725 s and t₂ = 0.2177 s. Find the values of k and b.
m
k b
Y
n
y(t) F.V.
t₁ t₂
t

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