### Problem 6**Title**: Problem 6: Computation of Tangent and Curve Lengths**Description**: This problem involves two parallel tangents that are 20 meters apart and connected by a reversed curve. The chord length from the Point of Curve (P.C.) to the Point of Tangent (P.T.) is specified to be 120 meters. The objective is to compute the following:1. **Length of Tangent with Common Direction**2. **Equal Radius of the Reversed Curve**3. **Stationing of the Point of Reversed Curve (P.R.C.)** - Given that the stationing of point A at the beginning of the tangent with a common direction is 2 + 240.**Note**: The text includes a placeholder with a green highlight which seems to be a reference or code, not directly related to the problem's calculations.**Graphical Representation (Explanation)**:- There are no graphs or diagrams provided in the text. However, if diagrams were present, they would likely show two parallel lines, 20 meters apart, joined by a reversed curve, and include: - Chord length between P.C. and P.T. as 120 meters. - Point A at the beginning of the tangent with a common direction. - Possible visual or numerical representation of the radii of the reversed curve and other critical measurements useful in solving the stated computations.**Steps for Computation**:1. **Length of Tangent with Common Direction**: This would involve geometric calculations typically using trigonometry and properties of circles and tangents.2. **Equal Radius of the Reversed Curve**: This would require solving equations involving radius and the given parallel distance.3. **Stationing of P.R.C.**: Involves calculation based on given stationing data and adjusting for the geometry of the reversed curve layout. **Educational Use**: This problem is useful in courses related to civil engineering, surveying, and transportation engineering to understand concepts of road and railway curve design.### ReferenceFor further reading and similar problem-solving examples, refer to textbooks on surveying and geometric design or curved alignment in civil engineering.

Distance between tangents = 20 m Chord length from PC to PT = 120 m

PROBLEM 6: Two parallel tangents 20m apart are connected by a reversed curve. The chord length from the P.C. to the P.T. equals 120m. Compute the following: ( a. The length of tangent with common direction. b. Equal radius of the reversed curve. c. The stationing of the P.R.C. if the stationing of A at the beginning of the tangent with common direction is 2+ 240.

PROBLEM 6: Two parallel tangents 20m apart are connected by a reversed curve. The chord length from the P.C. to the P.T. equals 120m. Compute the following: ( a. The length of tangent with common direction. b. Equal radius of the reversed curve. c. The stationing of the P.R.C. if the stationing of A at the beginning of the tangent with common direction is 2+ 240.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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