Problem 6: The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation F(x) = ax bx, where a = 45 N/m², b = 18 N/m, and the positive x direction is in the compression direction of the spring. ¹. Part (a) Write a general equation in terms of the given variables for the work required to compress this spring from equilibrium to any point xp. w = (a/3) (xp³) - (b/2) (xp²) ✓Correct! 6 Part (b) Calculate the work done, in joules, on the spring as it is compressed from x = 0 to x1 = 56 cm. No 1=-0.188 Wo-1=-0.1880 W1-25 ✓ Correct! Part (c) Calculate the work done, in joules, on the spring as it is compressed from x1 = 56 cm to x₂ = 88 cm. 0.870

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Problem 6: The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation F(x) = ax²
- bx, where a = 45 N/m², b = 18 N/m, and the positive x direction is in the compression direction of the spring.
Part (a) Write a general equation in terms of the given variables for the work required to compress this spring from equilibrium to any point xp.
w = (a/3) (xp³) - (b/2) (xp²) ✔Correct!
6 Part (b) Calculate the work done, in joules, on the spring as it is compressed from x = 0 to x1 = 56 cm.
No 1-0.188
Wo 1-0.1880 ✓ Correct!
Part (c) Calculate the work done, in joules, on the spring as it is compressed from x1 = 56 cm to x2 = 88 cm.
W1-2 = 0.870
Transcribed Image Text:Problem 6: The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation F(x) = ax² - bx, where a = 45 N/m², b = 18 N/m, and the positive x direction is in the compression direction of the spring. Part (a) Write a general equation in terms of the given variables for the work required to compress this spring from equilibrium to any point xp. w = (a/3) (xp³) - (b/2) (xp²) ✔Correct! 6 Part (b) Calculate the work done, in joules, on the spring as it is compressed from x = 0 to x1 = 56 cm. No 1-0.188 Wo 1-0.1880 ✓ Correct! Part (c) Calculate the work done, in joules, on the spring as it is compressed from x1 = 56 cm to x2 = 88 cm. W1-2 = 0.870
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