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Problem 6 Let X - Hyp(N, b, n), i.e. OCD () P{X = k} = if k € (0,...,n) else. Now let N, b→∞o in such a way that b/N-pe (0,1). Show that then P{X = k} – (*)p² (1-py-*. Explain the implications of this result for the concepts of sampling with and without replacement.

Problem 6 Let X - Hyp(N, b, n), i.e. OCD () P{X = k} = if k € (0,...,n) else. Now let N, b→∞o in such a way that b/N-pe (0,1). Show that then P{X = k} – (*)p² (1-py-*. Explain the implications of this result for the concepts of sampling with and without replacement.

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Problem 6 Let X - Hyp(N,b,n), i.e. C P{X = k} = if k € (0,...,n) else. Now let N, b→∞o in such a way that b/N-pe (0,1). Show that then P{X = k} - ("^ p² (1-py"-k. Explain the implications of this result for the concepts of sampling with and without replacement.
Transcribed Image Text:Problem 6 Let X - Hyp(N,b,n), i.e. C P{X = k} = if k € (0,...,n) else. Now let N, b→∞o in such a way that b/N-pe (0,1). Show that then P{X = k} - ("^ p² (1-py"-k. Explain the implications of this result for the concepts of sampling with and without replacement.
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