Problem 5 The standard Gibbs free energy change is 2.60 for the reaction at 25.0° mol C: kJ H2(g) + I2(9) 2 2HI(g); AGn = + 2.60 rxn mol The reaction starts with equal molar amounts of H,(g) and I,(g) in a previously evacuated, constant volume vessel. What is the equilibrium mole fraction of HI? Enter your answers in the box provided with correct units and sig. figs.: The equilibrium mole fraction of HI is Answer:

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Problem 5
The standard Gibbs free energy change is 2.60 K for the reaction at 25.0°
mol
С:
kJ
H2(g) + I2(9) 2 2Hl(g);
AGn = + 2.60
%3D
rxn
mol
The reaction starts with equal molar amounts of H,(g) and I,(g) in a previously evacuated, constant
volume vessel. What is the equilibrium mole fraction of HI? Enter your answers in the box provided with
correct units and sig. figs.:
The equilibrium
mole fraction
of HI is
Answer:
%3D
eq
Transcribed Image Text:Problem 5 The standard Gibbs free energy change is 2.60 K for the reaction at 25.0° mol С: kJ H2(g) + I2(9) 2 2Hl(g); AGn = + 2.60 %3D rxn mol The reaction starts with equal molar amounts of H,(g) and I,(g) in a previously evacuated, constant volume vessel. What is the equilibrium mole fraction of HI? Enter your answers in the box provided with correct units and sig. figs.: The equilibrium mole fraction of HI is Answer: %3D eq
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