Problem 5: Consider the following nonlinear differential equation: d²x dx dt² + 3x + 2x = f(x). dt If f(x) = sin(x), linearize the differential equation around x = π.

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Problem 5: Consider the following nonlinear differential equation:
d²x
dx
+ 3x + 2x
dt
f(x).
dt²
If f(x) = sin(x), linearize the differential equation around x = π.
=
Transcribed Image Text:Problem 5: Consider the following nonlinear differential equation: d²x dx + 3x + 2x dt f(x). dt² If f(x) = sin(x), linearize the differential equation around x = π. =
Expert Solution
Step 1: ''Introduction to the solution''

The   given differential  equation is  left parenthesis x apostrophe apostrophe plus 3 x x apostrophe plus 2 x right parenthesis equals sin x......... left parenthesis 1 right parenthesis space

We have to linearize  the given diffetrential  equation at  x equals pi.

Suppose that  x almost equal to x plus increment x commaincrement x rightwards arrowsmall  deviation from x.

Then, x apostrophe equals increment x apostrophe space space a n d space x apostrophe apostrophe equals increment x apostrophe apostrophe

Putting these values in (1) , we obtain, increment x apostrophe apostrophe plus 3 left parenthesis straight pi plus increment x right parenthesis increment x apostrophe plus 2 open parentheses straight pi plus increment straight x close parentheses equals sin open parentheses pi plus increment x close parentheses

                                                       rightwards double arrow increment x apostrophe apostrophe plus 3 straight pi increment straight x apostrophe plus 2 increment straight x equals negative 2 straight pi plus sin straight pi plus increment xcos straight pi [ignoring  higher  order terms]

                                                       rightwards double arrow increment x apostrophe apostrophe plus 3 straight pi increment straight x apostrophe plus 2 increment straight x equals negative 2 straight pi minus increment straight x

                                                       rightwards double arrow increment x apostrophe apostrophe plus 3 straight pi increment straight x apostrophe plus 3 increment straight x equals negative 2 straight pi.......... left parenthesis 2 right parenthesis

                                                      

                                                      

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