Problem 5: An ice skater is spinning at 5.4 rev/s and has a moment of inertia of 0.44 kg ⋅ m2. Part (a) Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 5.4 rev/s.Numeric : A numeric value is expected and not an expression.L1 = __________________________________________Part (b) He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 1.75 rev/s.Numeric : A numeric value is expected and not an expression.I2 = __________________________________________Part (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.75 rev/s. What is the magnitude of the average torque that was exerted, in N ⋅ m, if this takes 11 s?Numeric : A numeric value is expected and not an expression.τave = __________________________________________
Problem 5: An ice skater is spinning at 5.4 rev/s and has a moment of inertia of 0.44 kg ⋅ m2. Part (a) Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 5.4 rev/s.Numeric : A numeric value is expected and not an expression.L1 = __________________________________________Part (b) He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 1.75 rev/s.Numeric : A numeric value is expected and not an expression.I2 = __________________________________________Part (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.75 rev/s. What is the magnitude of the average torque that was exerted, in N ⋅ m, if this takes 11 s?Numeric : A numeric value is expected and not an expression.τave = __________________________________________
Problem 5: An ice skater is spinning at 5.4 rev/s and has a moment of inertia of 0.44 kg ⋅ m2. Part (a) Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 5.4 rev/s.Numeric : A numeric value is expected and not an expression.L1 = __________________________________________Part (b) He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 1.75 rev/s.Numeric : A numeric value is expected and not an expression.I2 = __________________________________________Part (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.75 rev/s. What is the magnitude of the average torque that was exerted, in N ⋅ m, if this takes 11 s?Numeric : A numeric value is expected and not an expression.τave = __________________________________________
Problem 5: An ice skater is spinning at 5.4 rev/s and has a moment of inertia of 0.44 kg ⋅ m2.
Part (a) Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 5.4 rev/s. Numeric : A numeric value is expected and not an expression. L1 = __________________________________________
Part (b) He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 1.75 rev/s. Numeric : A numeric value is expected and not an expression. I2 = __________________________________________
Part (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.75 rev/s. What is the magnitude of the average torque that was exerted, in N ⋅ m, if this takes 11 s? Numeric : A numeric value is expected and not an expression. τave = __________________________________________
Definition Definition Product of the moment of inertia and angular velocity of the rotating body: (L) = Iω Angular momentum is a vector quantity, and it has both magnitude and direction. The magnitude of angular momentum is represented by the length of the vector, and the direction is the same as the direction of angular velocity.
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