Problem 5: A thin rod of length L = 1.9 m lies along the positive y-axis with one end at the origin. The rod carries a uniformly distributed charge of Q1 = 5.2 µC. A point charge Q2 = 10.4 µC is located on the positive x-axis a distance a = 0.45 m from the origin. Refer to the figure. dy y Part (a) Consider a thin slice of the rod of thickness dy located a distance y away from the force on the point charge due to the charge on this thin slice? MultipleChoice : 1) Along the positive x-axis 2) Above the negative x-axis 3) Below the positive x-axis 4) Not enough information to determine 5) There is no force between the point charge and the slice of the rod 6) Above the positive x-axis 7) Below the negative x-axis Part (b) Choose the correct equation for x-component of the force, dFx, on the point ch SchematicChoice :

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Can you please solve (d) & (e)? 

Problem 5: A thin rod of length L = 1.9 m lies along the positive y-axis
with one end at the origin. The rod carries a uniformly distributed
charge of Q1 = 5.2 µC. A point charge Q2 = 10.4 uC is located on the
positive x-axis a distance a = 0.45 m from the origin. Refer to the figure.
dy
y
X
a
Part (a) Consider a thin slice of the rod of thickness dy located a distance y away from the origin. What is the direction of
the force on the point charge due to the charge on this thin slice?
MultipleChoice :
1) Along the positive x-axis
2) Above the negative x-axis
3) Below the positive x-axis
4) Not enough information to determine
5) There is no force between the point charge and the slice of the rod
6) Above the positive x-axis
7) Below the negative x-axis
Part (b) Choose the correct equation for x-component of the force, dFx, on the point charge due to the thin slice of the rod.
SchematicChoice :
kQ1Q2ady
Q1Q2ady
kQ,Q2ady dF
dF, =
L(a² + y²)
dFx
3
3
L(a² + y²)ž
L(a² + y²)ž
kQ1Q2ydy
kQ,Qzydy
Q1Q2ydy
L(a² + y²)
dF,
L(a² + y²)z
dFx
dFx
(a² + y²):
3
3
Part (c) Integrate the correct expression in part (b) over the length of the rod to find the x-component of the net force and
calculate its value, in newtons.
Numeric : A numeric value is expected and not an expression.
Fx =
Part (d) Choose the correct equation for the y-component of the force, dFy, on the point charge due to the thin slice of the
rod.
SchematicChoice :
kQ1Q2ady
kQ1Q2ady
dF,
L(a² + y²)ž
kQ1Q2ydy
dF,
L(a² + y²)z
dF,
3
3
3
L(a² + y²)z
kQ,Q2ady
L(a² + y²)
kQ1Q2ydy
dF,
kQ1Q2ady
dF,
L(a² + y²)ž
dF,
L(a² + y²)
Part (e) Integrate the correct expression in part (d) over the length of the rod to find the y-component of the net force and
calculate its value, in newtons.
Numeric : Anumeric value is expected and not an expression.
Fy =
Transcribed Image Text:Problem 5: A thin rod of length L = 1.9 m lies along the positive y-axis with one end at the origin. The rod carries a uniformly distributed charge of Q1 = 5.2 µC. A point charge Q2 = 10.4 uC is located on the positive x-axis a distance a = 0.45 m from the origin. Refer to the figure. dy y X a Part (a) Consider a thin slice of the rod of thickness dy located a distance y away from the origin. What is the direction of the force on the point charge due to the charge on this thin slice? MultipleChoice : 1) Along the positive x-axis 2) Above the negative x-axis 3) Below the positive x-axis 4) Not enough information to determine 5) There is no force between the point charge and the slice of the rod 6) Above the positive x-axis 7) Below the negative x-axis Part (b) Choose the correct equation for x-component of the force, dFx, on the point charge due to the thin slice of the rod. SchematicChoice : kQ1Q2ady Q1Q2ady kQ,Q2ady dF dF, = L(a² + y²) dFx 3 3 L(a² + y²)ž L(a² + y²)ž kQ1Q2ydy kQ,Qzydy Q1Q2ydy L(a² + y²) dF, L(a² + y²)z dFx dFx (a² + y²): 3 3 Part (c) Integrate the correct expression in part (b) over the length of the rod to find the x-component of the net force and calculate its value, in newtons. Numeric : A numeric value is expected and not an expression. Fx = Part (d) Choose the correct equation for the y-component of the force, dFy, on the point charge due to the thin slice of the rod. SchematicChoice : kQ1Q2ady kQ1Q2ady dF, L(a² + y²)ž kQ1Q2ydy dF, L(a² + y²)z dF, 3 3 3 L(a² + y²)z kQ,Q2ady L(a² + y²) kQ1Q2ydy dF, kQ1Q2ady dF, L(a² + y²)ž dF, L(a² + y²) Part (e) Integrate the correct expression in part (d) over the length of the rod to find the y-component of the net force and calculate its value, in newtons. Numeric : Anumeric value is expected and not an expression. Fy =
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